On a coordinate plane, the x-coordinate is negative and the y-coordinate is positive in which quadrant?

A rectangular picture frame has an area of 45 square inches. If it has a length of 7 and 1/2 inches, what is its width?

svetlana [45]

Answer:

Step-by-step explanation:

To find the width/length when you know the area and the length or width, you just divide the area by the known side.

45/7.5 = 6

7 0

3 years ago

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Hello i wanted to what 1,00000x20 is thank you for answering :)

Tema [17]

1,00000 x 20 = 2000000

Thanks

4 0

3 years ago

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What is the coefficient of 4(3)(2)Q

inysia [295]

Answer:

24

Step-by-step explanation:

4 x 3 = 12

12 x 2= 24

Coefficient is the number infront of the varible being multiplied. In this case 24 is the coefficient, and Q is the variable.

7 0

3 years ago

The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l

mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: $(\frac{n+1}{2}) th\ term$

Putting n=21

$(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term$

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

$Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5$

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

$Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151$

Now

<u>Interquartile Range:</u>

$IQR = Q_3-Q_1\\= 151-108.5\\=42.5$

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

#LearnwithBrianly

7 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of at the same time that water is being pumped into the tank at a con

Alexus [3.1K]

Water is leaking out of an inverted conical tank at a rate of 10,500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate at which water is being pumped into the tank

<h3><u>Answer:</u></h3>

The rate at which water is being pumped into the tank is 289,752 $cm^3/min$

<h3><u>Solution:</u></h3>

According to question,

There is an inverted conical tank, through which water is leaking at a rate of 10,500 cm3/min at the same time that water is being pumped into the tank at a constant rate

<em><u>The dimension of tank are: </u></em>

Diameter = 4cm

Radius(r) = $\frac{diameter}{2}$ = 2cm

Height = 6cm

Clearly we can see that height is 3 times radius so, we can write

h = 3r OR r = h/3 ……………………. (1)

<em><u>The volume of cone "V" is given as:</u></em>

$\text { volume of cone }(\mathrm{V})=\frac{1}{3} \pi r^{2} h$ -------- (2)

From (1) and (2)

$\text { Volume of cone(V) }=\frac{1}{3} \pi\left(\frac{h}{3}\right)^{2} h$

$\mathrm{V}=\frac{\pi h^{3}}{27}$ -------- (3)

<em><u>Now we calculate the derivate:- </u></em>

$\frac{d V}{d t}=\frac{3 \pi h^{2}}{27} \frac{d h}{d t}$

$\frac{d V}{d t}=\frac{\pi h^{2}}{9} \frac{d h}{d t}$ --------- (4)

According to question, when height is 2m = 200cm, the water level is rising at a rate of 20 cm/min

$\frac{d h}{d t}=20 \mathrm{cm} / \mathrm{min}$

On putting above values in equation(4) and solving we get

$\frac{d V}{d t}=279252$

Hence, the rate at which water is being pumped is 289,752 $cm^3/min$ which is the sum of water volume increasing at rate of 279,252 and 10,500 leaking out

3 0

3 years ago