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2 years ago

50PTS! Describe the vertical asymptotes and holes for the graph of y = x-5/x^2 -1

Mathematics

2 answers:

xeze [42]2 years ago

8 0

Answer:

yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Step-by-step explanation:

Diano4ka-milaya [45]2 years ago

3 0

Ok

first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0

then simplify
any factors you factored out is now a hole, remember them

to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve

so

y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0

no factors to simplify so no holes

set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1

x+1=0
x=-1

the horizontal assemtotes are x=1 and -1

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Alchen [17]

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3 years ago

The radius of a cylinder gift box is box is 3X +1 inches the height of the gift box is twice the radius what is the surface area

Genrish500 [490]

Answer:

The surface area of the gift box is = $A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}$

Step-by-step explanation:

The surface area of the cylinder can be calculated using this formula:

$A=2\pi rh+2\pi r^2$

in this case, r is not a number, but rather an expression, which is r = $3x +1$ .

The height of the gift box is twice the radius, which is h = $2(3x+1)= 6x+2$

To get our curved surface area, we carefully put the expressions for h and r into the equation.

$A = 2 \times \frac{22}{7} \times (3x+1) \times (6x+2) + 2 \times \frac{22}{7} \times (3x+1)^{2}$

$A = \frac{44}{7} (3x+1) \times (6x +2) + \frac{44}{7} (9x^{2} + 6x +1)\\A =\frac{132}{7}x + \frac{44}{7} \times (6x+2)+ \frac{396}{7}x^{2}+\frac{246}{7}x +\frac{44}{7}$

$A = \frac{792}{7}x^{2} +\frac{264}{7}x +\frac{264}{7}x + \frac{88}{7} + \frac{396}{7}x^{2} + \frac{246}{7}x + \frac{44}{7}$

$A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}$

The surface area of the gift box is = $A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}$

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3 years ago

Required information An article presents a new method for timing traffic signals in heavily traveled intersections. The effectiv

Natasha2012 [34]

Answer:

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=652.6$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=311.7 represent the sample standard deviation

n=50 represent the sample size

Soltuion to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=50-1=49$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,49)".And we see that $t_{\alpha/2}=2.01$

Now we have everything in order to replace into formula (1):

$652.6-2.01\frac{311.7}{\sqrt{50}}=563.997$

$652.6+2.01\frac{311.7}{\sqrt{50}}=741.203$

So on this case the 95% confidence interval would be given by (563.997;741.203)

6 0

2 years ago

Determine if (-2,6) and (4,12) are solutions to the system of equations:

kykrilka [37]

Answer:

Both $(-2,6)$ and $(4,12)$ are solutions to the system.

Step-by-step explanation:

In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.

Step 1: Plug $(-2,6)$ into $y=x+8$

$(6) = (-2)+8 = 6$

The solution verifies the equation.

Step 2: Plug $(-2,6)$ into $2y=x^2 + 8$

$2(6) = (-2)^2+8=4+8=12$

The solution verifies both equations. Therefore, $(-2,6)$ is a solution to this system.

Now we must check if the second point is also valid.

Step 3: Plug $(4,12)$ into $y=x+8$

$(12) = (4)+8 = 12$

Step 4: Plug $(4,12)$ into $2y=x^2 + 8$

$2(12) = (4)^2+8=16+8=24$

The solution verifies both equations. Therefore, $(4,12)$ is another solution to this system.

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2 years ago

Plssss helppp!!!!Find the value of x.

alina1380 [7]

Answer:

See how X looks similar to a obtuse angle? The angle looks an awful lot like it's around 40 degrees though, it seems to be an acute angle, they are less than 90* so anything near 90 should make sense. I'd say exactly 45.

Step-by-step explanation:

6 0

2 years ago

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