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3 years ago

Solve the equation (please show work if possible)

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

8 0

Answer:

I’m sorry I thought I saw a positive 3, The correct answer would be -10.

AURORKA [14]3 years ago

3 0

Answer:

-10

Step-by-step explanation:

imma be honest all i do is put in different numbers until it is right. But the way to do it is subract 2 by puting it under the negative 3 and you get -5. then multiply the 2 by putting it under the -5. you get -10. and the answer will read r = -10. Therefore r is -10

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What Percent Of 700 Is 385

Firlakuza [10]

$method\ \#1\\\\\begin{array}{ccc}700&-&100\%\\385&-&p\%\end{array}\ \ \ \ |cross\ myltiply\\\\700p=385\times100\\700p=38500\ \ \ \ \ |divide\ both\ sides\ by\ 700\\\\p=\frac{38500}{700}\\\\p=\frac{385}{7}\\\\\boxed{p=55\ (\%)}$

$method\ \#2\\\\\frac{385}{700}\times100\%=\frac{385}{7}\times1\%=55\times1\%=55\%$

3 0

3 years ago

Read 2 more answers

1. The curve y = (x - 1)(x – 5) cuts the x-axis at A and B and the y-axis at C.

saveliy_v [14]

So the first two questions are asking for points of intercept. a is asking where the function crosses the x, in this case it is where y=0. So your x intercept is at x= 1,5. Then to find the y intercept it is where x=0, so just substitute 0 for x. Then you get your y intercept as y=5. Because your coefficient for the quadratic function is positive your function has a minimum since it opens upward. I’m not sure what is means by C coordinate, but your vertex is at (3,-4) and lime of symmetry is at x=3.

X intercepts: (1,0) and (5,0)
Y intercept: (0,5)

3 0

2 years ago

Mystery Boxes: Breakout Rooms

ollegr [7]

Answer:

$\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}$

Step-by-step explanation:

Given

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}$

Required

Fill in the box

From the question, the range is:

$Range = 60$

Range is calculated as:

$Range = Highest - Least$

From the box, we have:

$Least = 1$

So:

$60 = Highest - 1$

$Highest = 60 +1$

$Highest = 61$

The box, becomes:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

From the question:

$IQR = 20$ --- interquartile range

This is calculated as:

$IQR = Q_3 - Q_1$

$Q_3$ is the median of the upper half while $Q_1$ is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}$

Upper half

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

The quartile is calculated by calculating the median for each of the above halves is calculated as:

$Median = \frac{N + 1}{2}th$

Where N = 7

So, we have:

$Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th$

So,

$Q_3$ = 4th item of the upper halves

$Q_1$ = 4th item of the lower halves

From the upper halves

$\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$

We have:

$Q_3 = 32$

$Q_1$ can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

$IQR = Q_3 - Q_1$

Where $Q_3 = 32$ and $IQR = 20$

So:

$20 = 32 - Q_1$

$Q_1 = 32 - 20$

$Q_1 = 12$

So, the lower half becomes:

Lower half:

$\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}$

From this, the updated values of the box is:

$\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}$