Help with this question answer them I will give you 15 pts.

Find the future value of 1000 at 7 % interest compounded annually for 10 years.

ser-zykov [4K]

The future value of 1000 with annual compounding for 10 years is $1967.15.

The formula for calculating with annual compounding is:

FV = P (1 + r)^n

FV = Future value
P = the amount deposited
R = interest rate
N = number of years

1000 x (1.07)^10 = $1967.15

To learn more about future value, please check: brainly.com/question/18760477

8 0

2 years ago

Read 2 more answers

Which relation is not a function?

kvv77 [185]

Answer:

B.

Step-by-step explanation:

You can't have the same X values for two different Y values

in this case 19 goes with 11 and 10 in the pairs (19,11) and (19,10)

6 0

3 years ago

a brownie recipe requires two and two thirds cups of sugar to one cup of chocolate chips. If one and one third cups of sugar is

Taya2010 [7]

Half of what the recipe required because your using half the required amount of sugar

4 0

4 years ago

Helppppp plzzzz ASAP!!!!!!<br> Thank you!!!!!!

Zielflug [23.3K]

Answer:

option 4.

16 square units

Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

S = (4 , 2)

we have to subtract the values of p from s

PS = (4 - 2 , 2 - 4)

PS = (2 , -2)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

PS^2 = 2^2 + -2^2

PS = √ 4 + 4

PS = √8

PS = 2√2

S = (4 , 2)

R = (8 , 6)

SR = (8-4 , 6-2)

SR = (4 , 4)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

SR^2 = 4^2 + 4^2

SR = √ (16 + 16)

SR = √32

SR = 4√2

having the values of 2 of its sides we multiply them and obtain their area

PS * RS = Area

2√2 * 4√2 =

16

3 0

4 years ago

According to a recent survey, the population distribution of number of years of education for self-employed individuals in a c

creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean $\mu$ and standard deviation $\sigma$ , then the distribution of sample mean will be normally distributed with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

b) mean and the standard for a random sample of size 49

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4$

c) mean and the standard for a random sample of size 196

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2$

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0

3 years ago