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3 years ago

How many inches are in 6 & a half yards

Mathematics

2 answers:

expeople1 [14]3 years ago

7 0

To find out how many inches in a yard.If you multiply by 36, it equals to 3 feet, or 0.9114 meters

Fittoniya [83]3 years ago

6 0

The anwser is 234 inches

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Helppppppppppppppp!!!!

alex41 [277]

Answer:

Step-by-step explanation:

i don’t see a picture?

8 0

3 years ago

If α, β are the zeroes of the polynomials f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) =

Pavlova-9 [17]

Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)explanation:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

4 0

2 years ago

What’s the answer?!!!!

mel-nik [20]

Answer: YES

Step-by-step explanation:

Concept

In a right triangle, the square of both legs is equal to the length of hypotenuse squared. This is the Pythagorean theorem: a²+b²=c². For more graphical explanation, please refer to the attachment below.

Given

Leg a = 36 in

Leg b = 48 in

Hypotenuse c = 60 in

Solve

a² + b² = c²

(36)² + (48)² = 3600

(60)² = 3600

3600 = 3600

Therefore, the answer is YES

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago

If S is the midpoint of RT, RS = 5x+7, and ST = 8x-31, find RS

Strike441 [17]

Answer:

38/3

Step-by-step explanation:

s is the midpoint of RT

so, RS = ST

5x + 7 = 8x -31

7+31 = 8x-5x

38= 3x

x= 38/3

8 0

2 years ago

Please explain how - calc ab - see attached photo

baherus [9]

Answer:

Step-by-step explanation:

Set up to different integrals that match the endpoints

so in our case it would look like

$\int\limits^0_{-2} {x} \, dx +\int\limits^1_0 {x+1} \, dx$

now it's just a matter of computing it

$\int\limits^0_{-2} {x} \, dx =x^2\\0^2-(-2)^2=4\\\int\limits^1_0 {x+1} \, dx =\frac{x^2}{2}+x\\\frac{1}{2}+1-0=\frac{3}{2}\\\frac{3}{2}+4=\frac{11}{2}$

4 0

2 years ago