Question

In the reaction 5 space B r to the power of minus space (a q )space plus space B r O subscript 3 to the power of minus space (a q )space plus space 6 space H to the power of plus space (a q )space rightwards arrow space 3 space B r subscript 2 space (a q )space plus space 3 space H subscript 2 O space (l )the rate of disappearance of Br- at some moment in time was determined to be 3.5 x 10-4 M/s. What is the rate of appearance of Br2 at that same moment

Answer 1

Answer:

$r_{Br_2}=2.1x10^{-4}M/s$

Explanation:

Hello,

In this case, for the reaction:

$5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)$

Thus, via the rate proportions between Br⁻ and Br₂ for which the stoichiometric coefficients are 5 and 3 respectively, we can write:

$\frac{r_{Br^-}}{-5} =\frac{r_{Br_2}}{3}$

Hence, the rate of appearance of Br₂ turns out:

$r_{Br_2}=\frac{3r_{Br^-}}{-5}=\frac{3*-3.5x10^{-4}M/s}{-5}\\ \\r_{Br_2}=2.1x10^{-4}M/s$

Take into account that the rate of disappearance is negative for reactants.

Best regards.