Answer:
Explanation:
Net force F = 1800 N
acceleration a = 1.5 m /s²
mass = m
mass = force / acceleration
= 1800 / 1.5
m = 1200 kg
I am currently learning this and I would say Suspensions!
Hope this helps :)
At the Freezing Point the particles in an object have no kinetic energy
<em>Answer:</em>
- Organic compounds are those which are derivatives of hydrocarbons. They are classified into following functional groups.
<em>Alkane: </em>
- Alkane are simplest hydrocarbons.
- They have general formula CnH2n+2. These hydrocarbons contain single bond.
- For example ethane , H3C----CH3.
<em>Alkene:</em>
- Alkene are most reactive.
- They have general formula CnH2n.
- These contain double bond in their structure.
- For example , ethene, H2C=CH2
<em>Alkyne:</em>
- These are less less reactive as compare to alkenes.
- They have general formula CnH2n-2.
- They contain triple bonds in their structure.
- For example Acetylene HC≡CH
<em>Alcohol:</em>
Alcohol have functional group OH. They have general formual R---OH, R may be alkyl group.For example Ethanol H3CH2C---OH
<em>Amine:</em>
- Amine contain NH2 F.G.
- They have general formula R---NH2.
- There are three types of amine like primary, secondary and tertiary amine.
- For example H3CH2C---NH2
<em>Aldehyde:</em>
- Aldehydes have CHO F.G .
- They have general formula R--CHO.
- For example H3CH2C---CHO
<em>Ketone:</em>
- Ketones have R--CO--R functional group.
- For example acetone H3C---CO---CH3
<em>Carboxylic acid:</em>
- They functional group COOH.
- Their general formula is R---COOH.
- For example Acetic acid H3C---COOH
Answer:
Final calculated molarity of the unknown acid be lower than the actual concentration.
Explanation:
Volume required unknown acid = V= 25.0 mL
Volume actually measure was more than V that is = V'
V' > V
Molarity of the solution is the moles of compound in 1 Liter solutions.
As we can see from the formula that molarity is inversely proportional to the volume of the solution.
- Molarity of solution decreases with increase in volume
- Molarity of solution Increases with decrease in volume.
We have added more volume than required which will be increase the volume of solution and the molarity of the solution will lower than the actual value.
