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allochka39001 [22]

2 years ago

9

The ratio of athletes to non-athletes at bayside high school is 2 to 6. If there are 1200 non-athletes at school, how many athle

tes are at bayside

1 answer:

N76 [4]2 years ago

4 0

Answer:

400

Step-by-step explanation:

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Assume that y varies directly with x. If y=9 when x=−3, find x when y=6.

Dafna1 [17]

Answer:-2

Step-by-step explanation:

8 0

2 years ago

Write the tangent, cosine and sine ratios of angles X & Y. Write each answer as a (reduced) fraction. Not a decimal.

Alisiya [41]

The tangent, cosine and sine ratios of angles X & Y in the reduced faction form is 3/4, 4/5 and 3/5 respectively.

<h3>What are the trigonometry ratios?</h3>

For a right angle triangle, the trigonometry ratios can be given as,

$\rm \sin \theta=\dfrac{b}{c}\\\rm \cos \theta=\dfrac{a}{c}\\\rm \tan \theta=\dfrac{b}{a}$

Here, <em>a</em> is base side<em>, b</em> is perpendicular side and<em> c</em> is the hypotenuse side of the triangle.

In the given triangle, the length of base side<em> </em>is 8 units, perpendicular side is 6 units and hypotenuse side is 10 units.

$a=8\\b=6\\c=10$

Thus, the tangent, cosine and sine ratios of angles X & Y are,

$\rm \sin \theta=\dfrac{6}{10}=\dfrac{3}{5}\\\rm \cos \theta=\dfrac{8}{10}=\dfrac{4}{5}\\\rm \tan \theta=\dfrac{6}{8}=\dfrac{3}{4}$

Thus, the tangent, cosine and sine ratios of angles X & Y in the reduced faction form is 3/4, 4/5 and 3/5 respectively.

Learn more about the trigonometry angles here;

brainly.com/question/20519838

#SPJ1

6 0

2 years ago

10(4-7) What is the value of =(4-1) ? <br>-10 <br>- 6<br> 6<br> 10

blagie [28]

Answer 10

This is the formula of an arithmetic sequence.
a
n
=
a
1
+
d
(
n
−
1
)
a
n
=
a
1
+
d
(
n
-
1
)
Substitute in the values of
a
1
=
1
a
1
=
1
and
d
=
3
d
=
3
.
a
n
=
1
+
(
3
)
(
n
−
1
)
a
n
=
1
+
(
3
)
(
n
-
1
)
Simplify each term.
a
n
=
1
+
3
n
−
3
a
n
=
1
+
3
n
-
3
Subtract
3
3
from
1
1
.
a
n
=
3
n
−
2

4 0

3 years ago

20 POINTS FOR WHOEVER ANSWERS FIRST-

Komok [63]

Okay so you take the number of weekdays to the number of weekends the ratio is 5:2 one month, which usually has 30 days which is 4 weeks tops so that is about 21 week days and and 9 weekends then times both by 12 you get 108 weekends and 252 weekdays i know that only equals 360 but this is a rough estimate so write that as a fraction 3/7 so there is a third that it will be on a weekday

4 0

3 years ago

A sector with a radius of 8 cm has an area of 56pi cm2. What is the central angle measure of the sector in radians?

Maurinko [17]

Answer:

$\frac{7\pi}{4}$ .

Step-by-step explanation:

Given information:

Radius of circle = 8 cm

Area of sector = $56\pi\text{ cm}^2$

Formula for area of sector is

$A=\dfrac{1}{2}\theta r^2$

where, r is radius and $\theta$ is central angle in radian.

Substitute $A=56\pi$ and r=8 in the above formula.

$56\pi=\dfrac{1}{2}\theta (8)^2$

$56\pi=\dfrac{64}{2}\theta$

$56\pi=32\theta$

$\dfrac{56\pi}{32}=\theta$

$\dfrac{7\pi}{4}=\theta$

Therefore, the measure of the sector in radians is $\frac{7\pi}{4}$ .

6 0

2 years ago