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2 years ago

Y-24=-7 i also need to be able to show my work and make sure its correct

1 answer:

german2 years ago

5 0

All you have to do is add 24 to both sides and you will get y. You add 24 so that it will cancel from one side but be added to the other.

The answer is y=17.

Hope this helps!

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-3x + 5y = 13<br> X + 4y = -10

Alex17521 [72]

X= -6
Y=-1
The x value is minus 6 and the y value is equal to minus 1

6 0

3 years ago

An IV infiltrates with 330 mL remaining in the bag. It was restarted at 1015 at a rate of 30 mL/hr. What is the IV completion ti

DochEvi [55]

Answer:

11 hours

Step-by-step explanation:

I came up with this answer by dividing the IV infiltrate in the bag by the rate. This gave the completion time.

Volume of IV infiltrate = 330ML

Rate at which it was running = 30 ML/hour

The IV completion time = volume/rate

= 330 ML/30 ML

= 11 hours

Therefore the IV completion time is 11 hours.

3 0

2 years ago

jennifer deposited $2500 in her savings account. her account compounds interest continuously at a rate of 6.5%. How long will it

kiruha [24]

Answer:

2.8 years

Step-by-step explanation:

continuous compounding formula:

A = Pe^rt

3000 = 2500e^.065t

ln(6/5) ÷ .065 ≈ 2.8 years

3 0

2 years ago

Solve for x. √x−11=5

kkurt [141]

X = 126

HOPE THIS HELPS!!!!!!!! :D

5 0

3 years ago

If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &8
\end{cases}$

$\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8
\\\\\\
\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r
\\\\\\
0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086
\\\\\\
r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}$

6 0

3 years ago