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ArbitrLikvidat [17]
3 years ago
13

28. (-2,-2) perpendicular to -5x + 2 = 3y - 9

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0
So the gradient is the negative reciprocal of the question so first you have to rearrange the equation into the form y = mx + c so you get 3y = - 5 x + 11 and then y = -5/3 x + 11/3. Now to find the gradient of the line perpendicular to it you do the negative reciprocal and get 3/5 x so now you have the equation y = 3/5 x + c . Now simply substitute your coordinate into the equation to get -2 = 3/5 x -2 + c and 3/5 x -2 is -1.2 so now you have 2 = -1.2 + c so c is 3.2 so your final equation is y = 3/5 x + 3.2 hope this helps :)
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Answer:

<em>Center: (3,3)</em>

<em>Radius: </em>2\sqrt{5}<em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

The distance between both points is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3

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d=\sqrt{(1-5)^2+(-1-7)^2}

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