A string is stretched between a fixed support and a pulley a distance 111 cm apart. The tension on the string is controlled by a
1 answer:
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Answer:
The intensity increased by a factor of 158489
Explanation:
Given that,
Sound level = 95.0 dB
Sound level = 43.0 dB
Frequency = 10000 Hz
We need to calculate the ratio of sound intensity
Using formula of sound level
Put the value into the formula
...(I)
.....(II)
Subtracting these equations
Taking inverse log
Hence, The intensity increased by a factor of 158489
Answer:
Frequency = 1,550Hz
Explanation:
To solve this we can use the equation:
(frequency = velocity/wavelength).
We are given the information that the wavelength is 22cm and the speed is 340m/s. The first step is to make sure everything is in the correct units (SI units), and to convert them if needed. The SI Units for velocity and wavelength are m/s and m respectively. This means we need to convert 22cm into meters, which we can do by dividing by 100, (as there are 100cm in a meter). 22/100 = 0.22m
Now we can substitute these values into the formula and calculate to solve:
Simplify to 3 significant figures:
f = 1,550Hz
(Which I believe is just below a G6 if you were interested)
Hope this helped!