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Irina18 [472]
3 years ago
14

A string is stretched between a fixed support and a pulley a distance 111 cm apart. The tension on the string is controlled by a

weight hanging from the string below the pulley. An electomechnical vibrator is used to vibrate the string at 120 Hz. When the weight is adjusted to 275 g, the string is found to oscillate in its third standing wave mode (three loops). What is the speed of wave propogation on the string in this mode?
Physics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

88.8 m/s= Speed of wave propagation in the required mode.(3 loops)

Explanation:

When there are 3 loops.  

the total length = L = 3 λ /2

⇒ λ  = 2 L / 3 = 2 ( 1.11 ) / 3 = 0.74 m

Velocity = v = f λ = (120)(0.74) = 88.8 m/s

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When a candle burns, which forms of energy does the chemical energy in the candle change to? A. light and sound B. heat and soun
Ratling [72]

Answer:

When a candle burns, the chemical energy in the candle changes to light energy and heat energy.<em> (C)</em>

Explanation:

Did you ever light a candle and have sound or electricity come out of it ? ?

3 0
3 years ago
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A sample neon gas has its volume tripled and its temperature held constant. What will be the new pressure relative to the initia
liberstina [14]

Answer:

Correct answer:  p₂ : p₁ = 1 : 3

Explanation:

A process that occurs at a constant temperature is called an isothermal process and the formula that applies to this process is:

p · V = const  where p is pressure and V is volume

Given : V₂ = 3 V₁

p₁ V₁ = p₂ V₂  ⇒ p₂ / p₁ = V₁ / V₂ ⇒  p₂ / p₁ = V₁ / 3 V₁ ⇒  p₂ / p₁ = 1 / 3

p₂ : p₁ = 1 : 3

which means that when the volume is increased three times the pressure is reduced three times

God is with you!!!

5 0
3 years ago
A 3.0 kg object is loaded into a toy spring gun, and the spring has a spring constant 750N/m. The object compresses the spring b
kiruha [24]

Answer:

Explanation:

mass of object, m = 3 kg

spring constant, K = 750 n/m

compression, x = 8 cm = 0.08 m

angle of gun, θ = 30°

(a) As the ball is launched, it has some velocity due to the compression in the spring, so it has some kinetic energy.

(b) Let v be th evelocity of ball at the tim eof launch.

by using the conservation of energy

1/2 Kx² = 1/2 mv²

750 x 0.08 x 0.08 = 3 x v²

v = 1.265 m/s

By use of the formula of maximum height

h = \frac{v^{2}Sin^{2}\theta}{2g}

h = \frac{1.265^{2}Sin^{2}30}{2\times 9.8}

h = 0.02 m

h = 2 cm  

4 0
3 years ago
Determine the kinetic energy of a 2000 kg roller coaster car that is moving at the speed of 10 ms
kondaur [170]

Answer:

\boxed {\boxed {\sf 100,000 \ Joules}}

Explanation:

Kinetic energy is energy due to motion. The formula is half the product of mass and velocity squared.

E_k= \frac{1}{2} mv^2

The mass of the roller coaster car is 2000 kilograms and the car is moving 10 meters per second.

  • m= 2000 kg
  • s= 10 m/s

Substitute these values into the formula.

E_k= \frac{1}{2} (2000 \ kg ) \times (10 \ m/s)^2

Solve the exponent.

  • (10 m/s)²= 10 m/s * 10 m/s= 100 m²/s²

E_k= \frac{1}{2} (2000 \ kg ) \times (100 \ m^2/s^2)

Multiply the first two numbers together.

E_k= 1000 \ kg  \times (100 \ m^2/s^2)

Multiply again.

E_k= 100,000 \ kg*m^2/s^2

  • 1 kilogram square meter per square second is equal to 1 Joule.
  • Our answer of 100,000 kg*m²/s² is equal to 100,000 Joules.

E_k= 100,000 \ J

The roller coaster car has <u>100,000 Joules</u> of kinetic energy.

3 0
3 years ago
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Studentka2010 [4]
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3 years ago
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