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Irina18 [472]
4 years ago
14

A string is stretched between a fixed support and a pulley a distance 111 cm apart. The tension on the string is controlled by a

weight hanging from the string below the pulley. An electomechnical vibrator is used to vibrate the string at 120 Hz. When the weight is adjusted to 275 g, the string is found to oscillate in its third standing wave mode (three loops). What is the speed of wave propogation on the string in this mode?
Physics
1 answer:
kvv77 [185]4 years ago
3 0

Answer:

88.8 m/s= Speed of wave propagation in the required mode.(3 loops)

Explanation:

When there are 3 loops.  

the total length = L = 3 λ /2

⇒ λ  = 2 L / 3 = 2 ( 1.11 ) / 3 = 0.74 m

Velocity = v = f λ = (120)(0.74) = 88.8 m/s

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While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the
Mademuasel [1]
<h2>18.6467 N</h2>

Explanation:

       The Work done by any force is defined as the force applied times the displacement of point of application of force in the direction of force.

       This is better represented as a scalar product of Force vector and displacement vector.

       Work\textrm{ = }\vec{F}.\vec{s}

Here, the angle between force and displacement is 145^{o}.

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If a 2kg ball has and initial velocity of
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Answer:

\boxed {\boxed {\sf 12 \ Newtons }}

Explanation:

Force is equal to the product of mass and acceleration.

F=m*a

We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.

1. Calculate Acceleration

Acceleration is the change in velocity over the change in time.

a=\frac{V_f-V_i}{t}

The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.

V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s

Substitute the values into the formula.

a=\frac{10 \ m/s-4 \ m/s }{1 \ s}

Solve the numerator.

a=\frac{6 \ m/s}{1 \ s }

Divide.

a= 6 \ m/s/s=6 \ m/s^2

2. Calculate Force

Now we know the acceleration and the mass.

m= 2 \ kg \\a= 6 \ m/s^2

Substitute the values into the fore formula.

F= 2 \ kg * 6  \ m/s^2

Multiply.

F= 12 \ kg*m/s^2

  • 1 kilogram meter per square second is equal to 1 Newton.
  • Our answer of 12 kg*m/s² is equal to 12 Newtons

F= 12 \  N

The force applies to the ball was <u>12 Newtons.</u>

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