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Nana76 [90]
3 years ago
10

Two cars are traveling in the same direction and with the same speed along a straight highway. Does either driver hear a differe

nt frequency from the other car's horn than they would if the cars were stationary
Physics
1 answer:
Trava [24]3 years ago
8 0

Answer:

No, either driver can not hear a different frequency from the other car's horn than they would if the cars were stationary.

Explanation:

Either driver hear a different frequency from the other car's horn than they would if the cars were stationary if two cars are traveling in the same direction and with the same speed along a straight highway because neither driver experiences a Doppler shift

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Describe the image of an object that is 38 cm from a concave mirror that has a focal length of 10 cm.
harina [27]
Let's start by using the mirror equation:
\frac{1}{f}= \frac{1}{d}+ \frac{1}{q}
where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:
\frac{1}{q}=  \frac{1}{f}- \frac{1}{d} =  \frac{1}{10 cm}- \frac{1}{38 cm}
from which we find q=13.6 cm.

The fact that q is positive means that the image is real, so it is on the same side of the object, with respect to the mirror.

Then we can also find the size of the image with respect to the original object. The magnification is given by
M=- \frac{q}{d} =- \frac{13.6}{38}=-0.36
The negative sign means that the image is inverted, and the size of the image is 0.36 times the size of the object.

4 0
3 years ago
TRUE OR FALSE- Doing sports activities as your Cardio Training can be just as effective or more effective than running on a trea
vivado [14]

its true

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6 0
3 years ago
If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
Mrrafil [7]

The magnitude of the electric field at this location is 1.5\times 10^{10} N/C

<u>Explanation:</u>

Given

Charge\ of\ the\ particle\ Q=4.3\times 10^-18\ C\\Force\ with\ which\ it\ is\ attracted\ F=6.5\times 10^-8\ N

Electric field at this location determined by the force and charge.

E=F/Q

E=\frac{6.5\times 10^-8}{4.3\times10^-18} =1.5\times\ 10^{10}  \ N/C

7 0
4 years ago
Jessie and Jaime complete a 5.0 km race. Each has a mass of 68 kg. Jessie runs the race at 15 km/h; Jaime walks it at 5 km/h. Ho
Leto [7]

The total metabolic energy used by each to complete the course is determined as 656.91 J.

<h3>Kinetic energy of Jessie and Jaime</h3>

The kinetic energy of Jessie and Jaime is calculated as follows;

K.E = ¹/₂mv²

where;

  • m is mass of Jaime
  • v is speed

15 km/h = 4.17 m/s

5 km/h = 1.39 m/s

K.E = ¹/₂(68)(4.17)² + ¹/₂(68)(1.39)²

K.E = 656.91 J

Thus, the total metabolic energy used by each to complete the course is determined as 656.91 J.

Learn more about kinetic energy here: brainly.com/question/25959744

5 0
2 years ago
Which Coefficients balance the following equation? ____Pb(OH)2+_____HCI—&gt; _____ H2O+______PbCl2
lorasvet [3.4K]

the answer is A it is so easy question

3 0
3 years ago
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