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Nana76 [90]
3 years ago
10

Two cars are traveling in the same direction and with the same speed along a straight highway. Does either driver hear a differe

nt frequency from the other car's horn than they would if the cars were stationary
Physics
1 answer:
Trava [24]3 years ago
8 0

Answer:

No, either driver can not hear a different frequency from the other car's horn than they would if the cars were stationary.

Explanation:

Either driver hear a different frequency from the other car's horn than they would if the cars were stationary if two cars are traveling in the same direction and with the same speed along a straight highway because neither driver experiences a Doppler shift

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Please find attached photograph for your answer. Hope it helps. Please do comment.

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3 years ago
An object is thrown with a horizontal velocity of 49.0 mt/sec and a vertical velocity 18.8 mt/sec. How long with the object take
UNO [17]

Answer:

49.0 x18.8 ur answer i think

Explanation:

7 0
3 years ago
Read 2 more answers
Two particles are traveling through space. At time t the first particle is at the point (−1 + t, 4 − t, −1 + 2t) and the second
Pie

Answer:

Yes, the paths of the two particles cross.

Location of path intersection = ( 1 , 2 , 3)

Explanation:

In order to find the point of intersection, we need to set both locations equal to one another. It should be noted however, that the time for each particle can vary as we are finding the point where the <u>paths</u> meet, not the point where the particles meet themselves.

So, we can name the time of the first particle T_F ,  and the time of the second particle T_S.

Setting the locations equal, we get the following equations to solve for T_F and T_S:

(-1 + T_F) = (-7 + 2T_S)                     Equation 1

(4 - T_F) = (-6 + 2T_S)                        Equation 2

(-1 + 2T_F) = (-1 + T_S)                     Equation 3

Solving these three equations simultaneously we get:

T_F = 2 seconds

T_S = 4 seconds

Since, we have an answer for when the trajectories cross, we know for a fact that they indeed do cross.

The point of crossing can be found by using the value of T_F or T_S in the location matrices. Doing this for the first particle we get:

Location of path intersection = ( -1 + 2 , 4 - 2 , -1 + 2(2) )

Location of path intersection = ( 1 , 2 , 3)

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3 years ago
In which type of circuit does charge move in only one direction?
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7 0
3 years ago
Which of the following statements are true about the lenses used in eyeglasses to correct nearsightedness and farsightedness? (T
Slav-nsk [51]

Answer:

A: They produce a real image.

Explanation:

The images formed on the retina of the eye for a normal visibility must always be real.

Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.

  • The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in  the case of farsightedness.
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3 years ago
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