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4 years ago

Which type of wave does the illustration depict?

Physics

2 answers:

NeX [460]4 years ago

5 0

Answer is B. Longitudinal Wave

Veronika [31]4 years ago

3 0

Answer : The correct option is, (b) longitudinal wave

Explanation :

Longitudinal waves : It is defined as the waves in which the particles of the medium move in the direction of the wave.

Transverse wave : It is defined as the waves in which the particles of the medium travel perpendicularly to the direction of the wave.

Surface wave : It is defined as a combination of transverse and longitudinal waves.

From the given image we conclude that, this illustration depict the longitudinal wave because the particles of the medium move in the direction of the wave.

Hence, the correct option is, (b) longitudinal wave

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3 years ago

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4 years ago

When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s . By how much has thermal energy increased duri

Advocard [28]

Complete question:

A fireman of mass 80 kg slides down a pole. When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s. By how much has thermal energy increased during his slide?

Answer:

The thermal energy increased by 3,099.2 J

Explanation:

Given;

mass of the fireman, m = 80 kg

initial position of the fireman, hi = 4.2 m

final speed, v = 2.2 m/s

The change in the thermal energy is calculated as;

ΔE + (K.Ef - K.Ei) + (Uf - Ui) = 0

where;

ΔE is the change in the thermal energy

K.Ef is the final kinetic energy

K.Ei is the initial kinetic energy

Uf is the final potential energy

Ui is the initial potential energy

$\Delta E_{th} + (\frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2) + (mgh_f - mgh_i)=0\\\\initial \ velocity, \ v_i = 0\\final \ height , \ h_f = o\\\\\Delta E_{th} + (\frac{1}{2} mv_f^2) + ( - mgh_i)=0\\\\\Delta E_{th} + \frac{1}{2} mv_f^2 - mgh_i = 0\\\\\Delta E_{th} =mgh_i - \frac{1}{2} mv_f^2\\\\\Delta E_{th} = 80 \times 9.8 \times 4.2 \ \ - \ \ \frac{1}{2} \times 80 \times (2.2)^2 \\\\\Delta E_{th} = 3292.8 \ J \ - \ 193.6 \ J\\\\\Delta E_{th} = 3,099.2 \ J$

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3 years ago