Answer:
Explanation:
Given
Cannon is fired with a velocity of
Using Equation of motion
where
after time
So after 3.3 s cannon ball is at a height of 185.89 m
Un electrón en un tubo de rayos catódicos acelera desde el reposo con una aceleración constante de 5.33x10¹²m/s² durante 0.150μs
1 answer:
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The period of a simple pendulum is given by:
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
(1)
We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.
We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
And its period is the reciprocal of its frequency:
So now we can use eq.(1) to find the gravitational acceleration of the planet:
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.
We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
And its period is the reciprocal of its frequency:
So now we can use eq.(1) to find the gravitational acceleration of the planet:
Speed=distance/time
distance =48km
time=2 hours
speed=48/2
=24km/h
speed=24km/h
FORMULAS
speed = distance/time
time = distance/speed
distance = speed×time
distance =48km
time=2 hours
speed=48/2
=24km/h
speed=24km/h
FORMULAS
speed = distance/time
time = distance/speed
distance = speed×time
Answer:
Explanation:
Please see attached file
