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Vedmedyk [2.9K]
4 years ago
10

Un electrón en un tubo de rayos catódicos acelera desde el reposo con una aceleración constante de 5.33x10¹²m/s² durante 0.150μs

(1μs-10⁻⁶s). El electrón se mueve otros 0.200μs a velocidad constante y, finalmente se para con una aceleración de -2.67x10¹³m/s² ¿Qué distancia recorre el electrón?
Physics
1 answer:
Andre45 [30]4 years ago
3 0
Can you translate that in English ? I'll try to help you out with that..
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To solve this problem we will apply the concept given by the law of gravitational attraction, which properly defines gravity under the function

g = \frac{GM}{r^2}

Here,

G = Gravitational Universal Constant

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r = Distance between the human and the center of mass of the Earth

The acceleration due to gravity when is 4 times the mass of Earth and 3 times the radius would be given as,

g_1 = \frac{GM}{r^2}

g_2 = \frac{G(4M)}{(3r)^2}

g_2 = \frac{4GM}{9r^2}

g_2 = \frac{4}{9} g_1

The weight is defined as

W = mg_1

So the new weight would be given as

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W' = m(\frac{4}{9} g_1 )

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W' = \frac{4}{9} W

W' = \frac{4}{9}(650)

W' = 288.8N

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Answer:

Explanation:

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Answer:

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