Answer: -1038.8 kJ
Explanation:
From the question, we can see that PV^n = constant. And as such, we can deduce that it is a polytropic process. Thus, we can use the polytropic work equation to calculate the needed work input.
from the question we were given
Mass of nitrogen, m = 7kg
initial temperature, T1 = 250k
Final temperature, T2 = 450k
Polytropic index, n = 1.4
Specific gas constant, R = 0.2968kJ/kgK
W = [p2 * v2 - p1 * v1] / 1 - n
W = [m * R * T2 - T1] / 1 - n
W = 7*0.2968*(450 - 250)] / 1 - 1.4
W = [7*0.2968*200] / -0.4
W = 415.52 / -0.4
W = -1038.8 kJ
Not necessarily, it just means that the Scientific theory was not complete and needs additional information, research, and ideas.
If you clap your hands, the shock causes the air around your hands to begin vibrating. When air particles vibrate, they bump into other particles near them. Then these particles begin to vibrate and bump into even more air particles. When the air particles begin vibrating the air inside your ear, you hear a sound.
Nuclear Fission s a power source with a very low environmental impact.
Answer:
a) laser 1 has the maximum closest to the central maximum
b) y₂ –y₁ = L 1.66 10⁻²
Explanation:
a), B1, B2) The expression that describes the constructive interference for a double slit is
d sin θ = m λ
The pattern is observed on a screen
tan θ = y / L
Since the angles are very small
tan θ = sin θ / cos θ = sin θ = y/L
d y / L = m λ
In this case the laser has a wavelength
λ
₁ = d/20
We substitute
d y / L = m d / 20
m = 1
y₁ = L / 20
For the laser 2 λ
₂= d / 15
y₂ = L / 15
When examining the two expressions, laser 1 has the maximum closest to the central maximum
b) the difference between the two patterns is
y₂- y₁ = L (1/15 - 1/20)
y₂ –y₁ = L 1.66 10⁻²
C) laser 1 second maximum
y₁ ’= 2 L / 20
y₁ ’= L 0.1
Laser 2 third minimum
To have a minimum, the equation must be satisfied
d sin θ = (m + ½) λ
d y / L = (m + ½) λ
d y / L = (m + ½) d / 15
y = L (m +1/2) / 15
m = 3
y₂’= L (3 + ½) / 15
y₂’= L 0.2333
The difference is
y₁ ’- y₂’ = L (0.1 - 0.2333)
y₁ ’–y₂’ = L (-0.133)
