Un electrón en un tubo de rayos catódicos acelera desde el reposo con una aceleración constante de 5.33x10¹²m/s² durante 0.150μs
1 answer:
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Answer:
Electric force,
Explanation:
Given that,
Electric charge 1,
Electric charge 2,
Distance,
To find,
The electric force between these two sets of charges.
Solution,
There exists a force between two electric charges and this force is called electrostatic force. It is equal to the product of electric charged divided by square of distance between them.
k is the electrostatic constant
So, the electric force between these two sets of charges is .
<h2>Hello!</h2>
The answer is: 8.62m
<h2>Why?</h2>There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.
<h2>First moment:</h2>Before the ball is thrown, where the potential energy is 0.
<h2>Second moment: </h2>After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.
Therefore,
Where:
<em>E</em> is the total energy
<em>PE</em> is the potential energy
<em>KE</em> is the kinetic energy
<em>m</em> is the mass of the object
<em>g</em> is the gravitational acceleration
<em>h </em>is the reached height of the object
<em>v</em> is the velocity of the object
Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:
Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.
So,
Hence,
The height at the second moment (maximum height) is 8.62m
Have a nice day!