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Step2247 [10]
3 years ago
14

A young man exerted a force of 9,000 N on a stalled car but was unable to move it. How much work was done?

Physics
1 answer:
olasank [31]3 years ago
5 0
W=F*s
W=9000*0
W=0
W:Work
F:Force
s:Distance
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y=y_{o}+V_{o} t-\frac{gt^{2}}{2}   (1)

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y=0  is the final height of the rocket (when it finally hits the launch pad)

V_{o}=0 is the initial velocity of the rocket (at the exact moment in which it stops the velocity is zero and then it begins to fall)

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0=520 m+0-\frac{9.8m/s^{2} t^{2}}{2}   (2)

t^{2}=\frac{-520 m}{-4.9 m/s^{2}}   (3)

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t=10.30 s   (5)  This is the time

c) Now we need to find the final velocity V_{f} for this rocket, and the following equation will be perfect to find it:

V_{f}=V_{o}-gt  (6)

V_{f}=0-(9.8 m/s^{2})(10.30 s)  (7)

V_{f}=-100.95 m/s  (8) This is the final velocity of the rocket. Note the negative sign indicates its direction is downwards (to the launch pad)

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