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Mumz [18]
2 years ago
12

PLEASE HELP!!

Mathematics
2 answers:
olga_2 [115]2 years ago
7 0

Answer:

28,716^3

Step-by-step explanation:

From the given, we need to determine the volume of a sphere. The sphere has a radius of 19 cm.

Calculation,

Sphere Volume = 4/3 * PI * radius^3, is the equation.

Substituting the given values,

Radius = 9 inches, PI = 3.14

volume = 4/3 * 3.14 * 19^3

volume = 28,716.34667 ^3

Therefore, the nearest centimeter is 28,716^3

ddd [48]2 years ago
3 0

Answer:

Sphere Volume = (4/3) * PI * radius^3

Volume = (4/3) * PI * 19^3

Volume = 28,730.9120146298

Volume = 28,731 (when using PI = 3.14159265...

Volume = 28,716.3466666667

Volume = 28,716 cc  answer is A.

Step-by-step explanation:

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timofeeve [1]

Step-by-step explanation:

In triangle ADE:

sum of all angles is 180.

3x-10+58+42=180

3x+90=180

3x=180-90

3x=90

x=90/3

x=30

As line DA and CB are parallel:

angle D=angle C

angle y=58

In angle BCE, sum of angles is 180.

z+58+42=180

z+100=180

z=180-100

z=80

4 0
3 years ago
Ml
Tanya [424]

Answer:

<em>The gold vein is  96 miles away from the farthest gold dust strike.</em>

Step-by-step explanation:

<u>Distance Between two Points in the Plane </u>

Given two points A(x,y) and B(w,z), the distance between them is:

d=\sqrt{(z-y)^2+(w-x)^2}

The prospector positioned the gold vein at  (-2,9) and the farthest gold dust strike at (94,9). We are required to calculate the distance between these two points. Use the formula:

d=\sqrt{(9-9)^2+(94-(-2))^2}

d=\sqrt{0^2+96^2}

d=\sqrt{96^2}=96

The distance is 96 units, but we know each unit on the graph represents 1 mile, thus the gold vein is 96 miles away from the farthest gold dust strike.

8 0
2 years ago
2x - 5y = - 15
UkoKoshka [18]

Answer:

2x+15=5y

y=(2x+15)/5

hope this helps

7 0
2 years ago
Read 2 more answers
Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio
Masja [62]

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2}  } }{N} }

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\

3. Caclulate Standard deviation:

SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2}  } }{5} }

SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251

7 0
2 years ago
Help plz its urgent.
soldi70 [24.7K]

Answer:

200 tax 33

Step-by-step explanation:

4 0
2 years ago
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