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7nadin3 [17]
3 years ago
10

Using Cramer's Rule, what is the value of x in the system of linear equations below?

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Answer:

0

Step-by-step explanation:

We find the determinant of a matrix by the method below. If we have a matrix:

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant is ad-bc

Now, using cramer's rule, we find x-value by the formula:

x=\frac{D_x}{D}

Where D is the determinant of the original problem and D_x is the determinant of the x-value matrix. How do we get those?

<u><em>To get original matrix and thus D, we set up the matrix as the coefficients of x and y (s) of both the equations and to get matrix of x-value and thus D_x, we replace the x values of the matrix with the numbers in the right hand side of the 2 equations.</em></u> We show this below:

<em />

<em>To get D:</em>

\left[\begin{array}{cc}3&4\\1&-6\end{array}\right] \\D=(3)(-6)-(1)(4)=-18-4=-22

<em>To get D_x:</em>

<em>\left[\begin{array}{cc}12&4\\-18&-6\end{array}\right] \\D_x=(12)(-6)-(-18)(4)=0</em>

<em />

<em>Putting into the formula, we get:</em>

<em>x=\frac{D_x}{D}=\frac{0}{-22}=0</em>

<em />

<em>Thus, the value of x is 0</em>

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Answer:

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Corrected question;

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Step-by-step explanation:

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