Answer:
terminal velocity is;
v = 117.54 m/s
v = 423.144 km/hr
Explanation:
Given the data in the question;
we know that, the force on a body due to gravity is;
= mg
where m is mass and g is acceleration due to gravity
Force of drag is;
= 
pCAv²
where p is the density of fluid, C is the drag coefficient, A is the area and v is the terminal velocity.
Terminal velocity is reach when the force of gravity is equal to the force of drag.
mg = pCAv²
we solve for v
v = √( 2mg / pCA )
so we substitute in our values
v = √( [2×(86 kg)×9.8 m/s² ] / [ 1.21 kg/m³ × 0.7 × 0.145 m²] )
v = √( 1685.6 / 0.122015 )
v = √( 13814.6949 )
v = 117.54 m/s
v = ( 117.54 m/s × 3.6 ) = 423.144 km/hr
Therefore terminal velocity is;
v = 117.54 m/s
v = 423.144 km/hr
Answer:
w = 1.976 rpm
Explanation:
For simulate the gravity we will use the centripetal aceleration 
, so:
where w is the angular aceleration and r the radius.
We know by the question that:
r = 60.5m
= 2.6m/s2
So, Replacing the data, and solving for w, we get:
W = 0.207 rad/s
Finally we change the angular velocity from rad/s to rpm as:
W = 0.207 rad/s = 0.207*60/(2
)= 1.976 rpm
Answer:solid
Explanation:And a solid the malicules are compact so they can move
Answer:
C. a quantity with magnitude and direction
Explanation:
These are the options for the question
A. a quantity of magnitude only
B. a quantity with direction only
C. a quantity with magnitude and direction
D. a quantity with no units.
Velocity is the distance cover per time, it is the rate at which an object change its position with respect to time.
Velocity is a vector quantity unlike speed which is a scalar quantity, velocity is the speed of an object with a specific direction.
For instance, the distance cover by Mr. A is 10m, at 2 seconds, this show a magnitude and direction, then velocity here is 10/2=5m/s
Answer:
the angle between the electron's velocity and the magnetic field is 19⁰
Explanation:
Given;
magnitude of the magnetic field, B = 83 x 10⁻⁵ T
acceleration of the electron, a = 34 x 10¹³ m/s²
speed of the electron, v = 72 x 10⁵ m/s
mass of electron, m = 9.11 x 10⁻³¹ kg
The magnetic force experienced by the electron is calculated as;
F = ma = qvB sinθ
where;
q is charge of electron = 1.602 x 10⁻¹⁹ C
θ is the angle between the electron's velocity and the magnetic field.
Therefore, the angle between the electron's velocity and the magnetic field is 19⁰
