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2 years ago

6

n the metric system the acceleration due to gravity near Earth's surface is about 9.81 meters per second per second. What is the

acceleration due to gravity as measured in the English system, that is, in feet per second per second? (Round your answer to one decimal place.)

1 answer:

Anna007 [38]2 years ago

3 0

Answer:

$32.2\frac{ft}{s^2}$

Explanation:

To do this conversion we have to know that:

$1ft=0.3048m$

(It is easy to find this value on physics textbooks or internet physics webpages)

So, we should convert the gravitational acceleration in the next way:

$9.81\frac{m}{s^{2}}=9.81\frac{m}{s^{2}}*\frac{1ft}{0.3048m}$

So, the meters cancel out:

$9.81\frac{m}{s^{2}}=9.81\frac{1}{s^{2}}*\frac{1ft}{0.3048}=32.18\frac{ft}{s^2}$

$9.81\frac{m}{s^{2}}=32.2\frac{ft}{s}$

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What is the magnite of the net displacement of the mouse?

agasfer [191]

Complete Question

A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?

Answer:

The values is $s = 7.49 \ m$

Explanation:

From the question we are told that

The distance it travels eastward is $x = 5.0 \ m$

The distance it travel towards the southeast is $l = 3.0\ m$

The distance it travel towards the south is $z = 1 \ m$

Let x-axis be east

y-axis south

z-axis into the ground

The angle made between east and south is $\theta = 45^o$

The displacement toward x-axis is

$x = 5 + 3cos(45)$

$x = 7.12$

The displacement toward the y-axis is

$y = 3 * sin (45)$

$y = 2.123$

Now the overall displacement of the rat is mathematically evaluated as

$s = \sqrt{7.12^2 + 2.12^2 + 1^2}$

$s = 7.49 \ m$

3 0

2 years ago

Amanda [17]

Answer:

The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.

Explanation:

The distance of the book before the lamp is moved, $d_{b} = 30 cm$

The distance of the book after the lamp is moved, $d_{a} = 90 cm$

Illumination can be given by the formula, $E = \frac{P}{4 \pi d^{2} }$

Illumination before the lamp is moved, $E_{b} = \frac{P}{4 \pi d_{b} ^{2} }$

Illumination after the lamp is moved, $E_{a} = \frac{P}{4 \pi d_{a} ^{2} }$

$\frac{E_{a}}{E_{b}} } = \frac{\frac{P}{4 \pi d_{a} ^{2} } }{\frac{P}{4 \pi d_{b} ^{2} } }$

$\frac{E_{a} }{E_{b} } = \frac{d_{b} ^{2} }{d_{a} ^{2}} \\\frac{E_{a} }{E_{b} } = \frac{30^{2} }{90 ^{2}}\\\frac{E_{a} }{E_{b} } =\frac{900 }{8100}\\\frac{E_{a} }{E_{b} } =\frac{1 }{9}$

$E_{b} = 9E_{a}$

The illumination on the book before the lamp is moved is 9 times the illumination after the lamp is moved.

6 0

2 years ago

A mountain-climber friend with a mass of 74 kg ponders the idea of attaching a helium-filled balloon to himself to effectively r

bazaltina [42]

Answer:

$V=16.65 m^3$

Explanation:

The volume of the balloon can be find compared the force in each cases so:

reduce 25% from 74kg

$R=\frac{25}{100}*74kg=18.5kg$

So the net force uproad on the balloon is

$F_b=18.5kg*g$

Now the density of the both gases air and helium are different however the volume is the same change offcorss the mass so:

$P_h=\frac{m}{V}=0.179 kg/m^3$

$P_A=1.29 kg/m^3$

$F_b=F_A-F_H$

$F_b=m_a*g-m_h*g$

$m=P/V$

$18.5kg*g=(1.29kg/m^3-0.179kg/m^3*)V*g$

$V=\frac{18.5kg}{(1.29-0.179)kg/m^3}$

$V=16.65 m^3$

4 0

2 years ago

What mass of water will fill a tank that is 100.0 cm long, 50.0 cm wide, and 30.0 cm high? Express the answer in grams.

Bond [772]

$calculate\ mass\ from\ formula\ for\ density:\\\\
density=volume*mass\\
mass=\frac{density}{volume}\\\\
volume=width*length*height\\
volume=100*50*30=150000cm^3=0,15m^3\\\\
density\ of\ water=\ 999.9720 \frac{kg}{m^3} \\\\mass=0,15*999.9720=149,9958kg=149995,8grams\\\\ Answer\ is\ :\\water\ which\ weight\ is\ equal\ to\ 149995,8grams.
$

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2 years ago

Pick an activity you enjoy, such as running or riding a scooter, and describe how newton's laws apply to that activity.

deff fn [24]

I like playing basketball. So I'm the object in motion. Until an unbalanced force comes and hits me I fall and stay at rest.

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3 years ago

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