Strange as it may seem, the object would keep moving, in a straight line and at the same speed, until it came near another object. Its momentum and kinetic energy would never change. It might continue like that for a billion years or more.
Have a look at Newton's first law of motion.
Answer:
Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.
Answer:
Waning Gibbous is correct
Answer:
A. 24 m, 14 m/s
B. 8.0 m
Explanation:
Given:
x₀ = 6.0 m
v₀ = 4.0 m/s
a = 5.0 m/s²
t = 2.0 s
A. Find: x and v
x = x₀ + v₀ t + ½ at²
x = (6.0 m) + (4.0 m/s) (2.0 s) + ½ (5.0 m/s²) (2.0 m/s)²
x = 24 m
v = at + v₀
v = (5.0 m/s²) (2.0 s) + (4.0 m/s)
v = 14 m/s
B. Find x when v = 6.0 m/s.
v² = v₀² + 2a (x − x₀)
(6.0 m/s)² = (4.0 m/s)² + 2 (5.0 m/s²) (x − 6.0 m)
x = 8.0 m
The time for the police car to catch up with the speeding motorist is 7.6 seconds.
<h3>What time will the police car catch up with the speeding motorist?</h3>
The police car and the motorist will cover equal distances.
Let the distance covered be d.
Distance covered by the motorist = speed * time
time = t, speed = 30 m/s
d = 30t
Distance covered by the police car = acceleration * (time)
time = t - 2, acceleration = 5.0 m/s²
d = 5(t-2)²
d = 5(t² - 4t + 4)
d = 5t² - 20t + 20
Equating the two equations for distance
5t² - 20t + 20 = 30t
5t² - 50t + 20 = 0
Solving for t using the quadratic formula:
t = 9.6 second or 0.4 seconds
Since t > 2, t = 9.6 seconds
t - 2 = 9.6 - 2
t - 2 = 7.6 seconds
Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.
Learn more about distance and acceleration at: brainly.com/question/14344386
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