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zysi [14]
3 years ago
6

What would it be like to walk on Venus?

Physics
1 answer:
maria [59]3 years ago
3 0

it will be very hot so that causes nobody to walk on venus because its the hottest outer planet.

hope I helped :)

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Distributions of electric charges in a cell play a role in moving ions into and out of a cell. In this situation, the motion of
Y_Kistochka [10]

Answer:

An atom is the smallest constituent unit of ordinary matter that constitutes a chemical element. Every solid, liquid, gas, and plasma is composed of neutral or ionized atoms. Atoms are extremely small; typical sizes are around 100 picometers.Explanation:

7 0
3 years ago
I need help in this small question:
Natali5045456 [20]

Answer:

1) The energy released during nuclear fission or fusion, especially when used to generate electricity is called nuclear energy.

2) It is not renewable because it is an element that has no way whatsoever to regenerate or replicate itself, nor gets created by any natural terrestrial means, neither makes itself available by arriving from outer space (like sunlight). There is a limited amount of it available on the Earth, and every bit you use is a bit you’ll never have available again (as Uranium atoms get destroyed by the fission process).

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5 0
3 years ago
At a race car driving event, a staff member notices that the skid marks left by the race car are
krok68 [10]

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

A car experiences a deceleration (a) of -41.62 m/s² and comes to a stop (final velocity = v = 0 m/s) after 10.99 m (s).

We can calculate the initial velocity of the car (u) using the following kinematic equation.

v^{2} = u^{2} + 2as\\\\u = \sqrt[]{v^{2}-2as} = \sqrt[]{(0m/s)^{2}-2(-42.61m/s^{2} )(10.99m)} = 30.60m/s

A car that experiences a deceleration of -41.62 m/s² and comes to a stop after 10.99 m has an initial velocity of 30.60 m/s.

Learn more: brainly.com/question/14851168

5 0
2 years ago
Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to
Deffense [45]

Answer:

P2 = 128,205 pascal.

Explanation:

<u>Given the following data;</u>

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

<em>Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas. </em>

Mathematically, Gay Lussac's law is given by;

PT = K

Where;

  • P represents pressure.
  • T represents temperature.
  • K is the constant of proportionality.

\frac{P1}{T1} = \frac{P2}{T2}

<em>Making P2 as the subject formula, we have;</em>

P_{2}= \frac{P1}{T1} * T_{2}

Substituting into the equation, we have;

P_{2}= \frac{100000}{273} * 350

P_{2}= 366.3004* 350

P2 = 128205.13 ≈ 128205 pascal.

<em>Therefore, the pressure inside the hot water bottle is 128,205 pascal. </em>

5 0
2 years ago
What is a force on the object if it has a mass of 10.41 kg and an acceleration of 6.5 m/s2
Fudgin [204]
To determine the force of the system, we use Newton's Second Law of motion which relates force and mass where they are directly proportional and the constant of proportionality is the acceleration. We calculate as follows:

F = ma
F = 10.41 kg ( 6.5 m/s^2 )
F = 67.67 kg m / s^2 or N
4 0
3 years ago
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