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Sergeeva-Olga [200]
3 years ago
15

What is the ratio of 22 hours to 24 hours in a day in lowest terms?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The ratio in lowest terms is 11 hours to 12 hours.

Both 22 and 24 can be divided by 2:

22 ÷ 2 = 11

24 ÷ 2 = 12

11 hours to 12 hours

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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Font
balu736 [363]

Answer:

A. 4.2 times

Step-by-step explanation:

Chlorine level of the pool as adjusted by Paula = 6.3 parts per million

Ideal Chlorine level as suggested by the magazine = 1.5 parts per million.

Thus, the number of times the ideal level of Chlorine that the current level is = current level ÷ ideal level

= \frac{6.3}{1.5} = 4.2

The current Chlorine level is 4.2 times the ideal Chlorine level.

7 0
3 years ago
PLEASE HELP 7TH GRADE 100 PTS!!!
MariettaO [177]

f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.

f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.

So for Section A:

f(x) = 5x, (0,1)

[f(1) - f(0)]/(1-0)

= [5(1) - 5(0)]/1

=(5)/1

=5

Do the same for section B and you'll get 5 as well.

I hope this helps you because I have no clue if my answer is right

6 0
3 years ago
What are the zeros of the polynomial function f(x) = x3 + 2x2 − 24x?
Alik [6]

You may notice that all of the terms have a common factor: x. So, let's take the x out of all the terms. This gives us:

x(x^2 + 2x - 24) = 0


Using the Zero Product Property, we can say that both x = 0 and x^2 + 2x - 24 = 0.

Let's solve both. x = 0 is obvious, but we still need to solve our other term:

x^2 + 2x - 24 = 0

  • Set up

(x + 6)(x - 4) = 0

  • Factor

x = -6, 4

  • Apply the Zero Product Property

Our answer is x = -6, 0, 4.


4 0
3 years ago
If you can solve it.Thanks in advance
vivado [14]

Answer:

f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}

Step-by-step explanation:

we have

f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}

g(x)=\frac{1}{x^{2}+1}

we know that

In the function

f(g(x))

The variable of the function f is now the function g(x)

substitute

f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}

f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}

4 0
3 years ago
What is the equation of the following line written in general form?
AlekseyPX

Answer:

add 1;6 and 6,2 hope this helps ;)

8 0
3 years ago
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