Answer:
A. 4.2 times
Step-by-step explanation:
Chlorine level of the pool as adjusted by Paula = 6.3 parts per million
Ideal Chlorine level as suggested by the magazine = 1.5 parts per million.
Thus, the number of times the ideal level of Chlorine that the current level is = current level ÷ ideal level
= 
The current Chlorine level is 4.2 times the ideal Chlorine level.
f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.
f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.
So for Section A:
f(x) = 5x, (0,1)
[f(1) - f(0)]/(1-0)
= [5(1) - 5(0)]/1
=(5)/1
=5
Do the same for section B and you'll get 5 as well.
I hope this helps you because I have no clue if my answer is right
You may notice that all of the terms have a common factor:
. So, let's take the
out of all the terms. This gives us:

Using the Zero Product Property, we can say that both
and
.
Let's solve both.
is obvious, but we still need to solve our other term:



- Apply the Zero Product Property
Our answer is x = -6, 0, 4.
Answer:
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)
Step-by-step explanation:
we have
![f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)

we know that
In the function

The variable of the function f is now the function g(x)
substitute
![f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%5E%7B2%7D%20%2B%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B%28%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%2B1%7D%29%7D%7D)
![f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3D%5Cfrac%7B1%7D%7B%28x%5E%7B2%7D%2B1%29%5E%7B2%7D%7D%20%2B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%2B1%7D)
Answer:
add 1;6 and 6,2 hope this helps ;)