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3 years ago

I WAS ONLY ABLE TO SELECT 40 PTS THIS TIME, PLS ANSWER THIS ONE IT HAS THE PICTURE WITH IT.

Mathematics

2 answers:

lara31 [8.8K]3 years ago

6 0

∠1 and 105° are supplementary angles. (supplementary = 180°)

180 - 105 = 75°

∠1 = 75°

∠1 and ∠2 are corresponding angles, and so there measurements will be the same

∠1 = ∠2
∠1 = 75°
∠2 = 75°

105° and ∠3 are same side, and are corresponding angles. Therefore, ∠3 = 105°

m∠1=75°

180° (the measurement of a straight angle).

Subtract the 105° (given) from the straight angle

180 - 105 = 75

m∠1=75°

hope this helps

BaLLatris [955]3 years ago

4 0

Okay so the first one is right.
The second one is wrong.
the third one is right.
The forth one is wrong.

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Suzie paid a total of $324 dollar sign, 324 for x tickets to a rock festival.

MA_775_DIABLO [31]

Find the ticket unit cost: divide the total paid, $324, by the number of tickets, x. Then the form of the unit cost is

$324

--------- .

This question is highly unusual in that you write "x" as the number of tickets sold, instead of a specific number of tickets. Supposing that you'd sold 100 tickets for $324, then the unit cost would be, much more typically, a numeric ratio:

$324

----------------- = $3.24/ticket

100 tickets

6 0

4 years ago

Read 2 more answers

A private shipping company will accept a box for domestic shipment only if the sum of its length and girth (distance around) do

aivan3 [116]

Answer:

18×18×36

Step-by-step explanation:

According to the Question

108≥ 4h + w

Volume V is given by

V = wh^2

⇒V= (108-4h)h^2

⇒V= 108h^2 - 4h^3

Now differentiating and keeping = 0 we get

V' = 216h - 12h^2 = 0

h = 216/12 = 18

w = 108 - 4×18 = 36

V = 36×18^2 = 11664 from a box of 18×18×36.

5 0

3 years ago

What is the sum of the first 51 consecutive odd positive integers?

Angelina_Jolie [31]

We call:

$a_{n}$ as the set of the first 51 consecutive odd positive integers, so:

 $a_{n} = \{1, 3, 5, 7, 9...\}$

Where:
$a_{1} = 1$
$a_{2} = 3$
$a_{3} = 5$
$a_{4} = 7$
$a_{5} = 9$
and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

 $a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}$

Then:

 $a_{n} = a_{1} + (n-1)d$

So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

 $S_{k} = ( \frac{a_{1} + a_{k}}{2} ).k$

Therefore, we need to find:
 $a_{k} = a_{51}$

Given that $a_{1} = 1$ , then:

$a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1$

Thus:
$a_{k} = a_{51} = 2(51)-1 = 101$

Lastly:

$S_{51} = ( \frac{1 + 101}{2} ).51 = 2601$

4 0

3 years ago

I really need help plz help me ✌️️

OLEGan [10]

The answer is 7/4. Hope this helps! :)

6 0

4 years ago

Read 2 more answers

Andru [333]

Answer: 6 to 48

Step-by-step explanation:

1 x 6 = 6

8 x 6 = 48

(pls mark me brainliest)

4 0

3 years ago