Multiplying monomials and binomials

Mathematics

1 answer:

lubasha [3.4K]2 years ago

7 0

Answer:

$28w^2-476w$

Step-by-step explanation:

The general rule we are going to use to multiply this out is the distributive property. Which is:

a(b+c) = ab + ac

<u>Note:</u> x * x = x^2

Now multiplying, we get:

$28w(w-17)\\=28w*w-28w*17\\=28w^2-476w$

This is the multiplied out form, answer.

You might be interested in

Fido wants to buy a new car. He will need to get a car loan. Fido decides to wait for a few months until his credit history

Marta_Voda [28]

Answer:

Fido's decision is sensible because the cost of the car loan should be less this credit history improves

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please help with math

irakobra [83]

Answer:

5 and 6

Step-by-step explanation:

You have to find two numbers (in the chart) that have a difference of 3/8.

This is just one possiblity, there are other correct answers.

There is size 5 and 6. 9 and 4/8-9 and 1/8=3/8.

8 0

2 years ago

Find the quotient of 21x^2y^6+6xy^3-30xy/3xy.

kaheart [24]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------$

$\bf \cfrac{21x^2y^6+6xy^3-30xy}{3xy}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{21x^2y^6}{3xy}+\cfrac{6xy^3}{3xy}-\cfrac{30xy}{3xy}}
\\\\\\
\cfrac{21}{3}\cdot x^2x^{-1}y^6y^{-1}+\cfrac{6}{3}\cdot x^1x^{-1}y^3y^{-1}-\cfrac{30}{3}\cdot x^1x^{-1}y^1y^{-1}
\\\\\\
7x^{2-1}y^{6-1}+2x^{1-1}y^{3-1}-10x^{1-1}y^{1-1}\implies 7xy^5+2y^2-10$

3 0

2 years ago

Read 2 more answers

The steps for solving the equation 2x-3=7

saw5 [17]

Step 1: Add 3 to both sides.

2x-3+3=7+3

2x=10

Step 2: Divide both sides by 2.

2x/2=10/2

x=5

3 0