Answer:
13
Step-by-step explanation:
On a given line, (on one side) there are a total of 180°
if one line in Problem #3 is bisected by a line, with one half X and the other 120°,
do 180° (the total) minus 120° which=60°
now the hard part, that line that bisected the first line is bisecting a line that is parallel to your second line, the one with <5 and <6
this means that the big angle formed in the first one with 120° is the same angle as in the second line, leaving <5 as 120°
which means <6 is 60°, like in the top part of the problem. You're basically flipping the top line upside down, I hope it helps.
(n - 2)*180
Therefore, (8 - 2)*180
Which equals to 6(180) or 1080
Hope this helps! :)
Answer:

Step-by-step explanation:
For this case we know that:

And we want to find the value for
, so then we can use the following basic identity:

And if we solve for
we got:


And if we replace the value given we got:

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:
