In the given question according to the information the process of polymerization is an addition polymerization.
<h3>What is polymerization?</h3>
Polymerization is a process in which addition of many small molecules takes place for the formation of a large three dimensional substance known as polymer.
In the polymerization of polyethene the small repeating molecule is ethene and in this process product formed due to the addition process to the double bond of the ethene.
- In condensation polymerisation removal of water molecule or any other molecule takes place.
- In dehydrogenation polymerisation removal of hydrogen molecule takes place.
- In dehydrohalogenation polymerisation removal of hydrogen halide molecule takes place.
Hence given process is an addition polymerisation.
To know more about polymerisation, visit the below link:
brainly.com/question/17932602
Answer:
Niels Bohr states that the line spectrum of the hydrogen atom by assuming that the electron revolve in circular paths and that the paths have an allowable radii. ...
Explanation:
discuss the origin of the line citing the bohr theory of the atom specify any energy transitions that are applicable
Niels Bohr states that the line spectrum of the hydrogen atom by assuming that the electron revolve in circular orbits and that orbits have an allowable radii. ... an absorption spectrum is produced, dark lines in the same position as the bright lines in the emission spectrum of an element are produced.
Bohr Atomic Model. Bohr Atomic Model : In 1913 Bohr proposed his quantized shell model of the atom to explain how electrons can have stable orbits around the nucleus. ... The atom will be stable in the state with the smallest orbit
Bohr explains to us that electron revolve round the nuclues of an atom and possess energy levels. they can change energy levels
Answer:
first we add the same direction. 12N + 32 N=44N .
then we add the forces. 54 up + 44N down= 10N up
Answer:
final concentration: Ca = 0.014 M
Explanation:
Velocity of reaction:
∴ α: order of reaction, assuming α = 1
∴ K = 0.249 s-1.......rate constant
∴ Cao = 0.050 M......initial concentration
∴ t = 5 s.......reaction time
⇒ δCa/δt = K*Ca
⇒ ∫δCa/Ca = K*∫δt
⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245
⇒ Cao/Ca = 3.473
⇒ Ca = 0.050/3.473
⇒ Ca = 0.014 M
