Answer:
Pb(NO3)2 + 2NaCl = 2NaNO3 + PbCl2
Answer:
157.64 L
Explanation:
We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 30 °C
T(K) = 30 °C + 273
T (K) = 303 K
Next, we shall convert 600 mmHg to atm. This can be obtained as follow:
760 mmHg = 1 atm
Therefore,
600 mmHg = 600 mmHg × 1 atm / 760 mmHg
600 mmHg = 0.789 atm
Finally, we shall determine the volume of the gas. This can be obtained as follow:
Number of mole (n) = 5 moles
Temperature (T) = 303 K
Pressure (P) = 0.789 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
PV = nRT
0.789 × V = 5 × 0.0821 × 303
0.789 × V = 124.3815
Divide both side by 0.789
V = 124.3815 / 0.789
V = 157.64 L
Therefore, the volume of the gas is 157.64 L
Answer:
B. 13.7 mm
Explanation:
by similarity of rectangular triangles, we have:
(1) Δ ABC and Δ AB'C'
∴ AB/AB' = AC/AC'
∴ hypotenuse (AB)² = AC² + BC².....Pythagorean theorem
⇒ AB² = (51 mm)² + (13 mm)²
⇒ AB² = 2770 mm²
⇒ AB = 52.63 mm
(2) Δ AB'C' :
∴ hypotenuse (AB')² = AC'² + B'C'²
∴ B'C' = 3.5 mm
from (1):
⇒ AB' = (AB)(AC') / AC = (52.63)(AC') / (51 mm)
⇒ AB' = 1.032AC'.......(3)
(3) in (2):
⇒ (1.032AC')² = AC'² + (3.5)²
⇒1.065AC'² = AC'² + 12.25
⇒ 0.065AC'² = 12.25
⇒ AC'² = 188.462
⇒ AC' = √188.462
⇒ AC' = 13.72 mm
They are produced by vacuum tubes devices that operate on the ballistic motion of electron controlled by electric fields
The exosphere is the uppermost layer of Earth's atmosphere
