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Archy [21]
4 years ago
13

Write a balanced chemical equation (smallest integer coefficients possible) for the reaction between an acid and a base that lea

ds to the production of Ca(ClO4)2(aq). Use the pull-down boxes for states. Give the names of the acid, the base, and the salt.
Chemistry
1 answer:
11Alexandr11 [23.1K]4 years ago
6 0

Answer:

2HClO4(aq) + Ca(OH)2(aq) → Ca(ClO4)2(aq) + 2H2O(l)

Perchloric acid + Calcium hydroxide → Calcium perchlorate + Water.

Explanation:

This is a neutralization reaction where the acid, Perchloric acid reacts completely with an appropriate amount of base, aqueous Calcium hydroxide to produce salt, aqueous Calcium perchlorate and water, liquid H2O only.

During this reaction, the hydrogen ion, H+, from the HClO4 is neutralized by the hydroxide ion, OH-, from the Ca(OH)2 to form the water molecule, H2O.

Thus, it is called a neutralization reaction.

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Can a chemical be decomposed chemically
marishachu [46]
It will depend on the chemical, if it's a chemical compound, yes it can be decomposed chemically into simpler substances, further elements that constitute or make up the given compound.

Mixtures are separated by physical means as there are still separate entities as the substances required to make the mixture do not chemically combine or become altered chemically.

Elements cannot be decomposed into simpler substances as the simplest substance of matter is an element itself. This cannot be decomposed by chemical means.
8 0
3 years ago
­­2K + 2HBr → 2 KBr + H2
Inessa [10]

Answer:

\large \boxed{\text{0.0503 g}}

Explanation:

The limiting reactant is the reactant that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:   39.10    80.41                2.016  

            2K  +  2HBr ⟶ 2KBr + H₂

m/g:     5.5      4.04

a) Limiting reactant

(i) Calculate the moles of each reactant  

\text{Moles of K} = \text{5.5 g} \times \dfrac{\text{1 mol}}{\text{31.10 g}} = \text{0.141 mol K}\\\\\text{Moles of HBr} = \text{4.04 g} \times \dfrac{\text{1 mol}}{\text{80.91 g}} = \text{0.049 93 mol HBr}

(ii) Calculate the moles of H₂ we can obtain from each reactant.

From K:  

The molar ratio of H₂:K is 1:2.

\text{Moles of H}_{2} = \text{0.141 mol K} \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol K}} = \text{0.0703 mol H}_{2}

From HBr:  

The molar ratio of H₂:HBr is 3:2.  

\text{Moles of H}_{2} = \text{0.049.93 mol HBr } \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol HBr}} = \text{0.024 97 mol H}_{2}

(iii) Identify the limiting reactant

HBr is the limiting reactant because it gives the smaller amount of NH₃.

b) Excess reactant

The excess reactant is K.

c) Mass of H₂

\text{Mass of H}_{2} = \text{0.024 97 mol H}_{2} \times \dfrac{\text{2.016 g H}_{2}}{\text{1 mol H}_{2}} = \textbf{0.0503 g H}_{2}\\ \text{The mass of hydrogen is $\large \boxed{\textbf{0.0503 g}}$ }

3 0
3 years ago
Write the balanced complete ionic equation for the reaction hcho2(aq)+koh(aq)→
baherus [9]
<span>Answer: Molecular: HC2H3O2(aq) + KOH(aq) --> KC2H3O2(aq) + H2O(l) Complete ionic: HC2H3O2(aq) + K+(aq) + OH-(aq) --> K+(aq) + C2H3O2-(aq) + H2O(l) Net Ionic: HC2H3O2(aq) + OH-(aq) --> C2H3O2-(aq) + H2O(l)</span>
4 0
3 years ago
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Which two statements describe organ systems working together to remove
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I think the answer is D
4 0
4 years ago
Which statement best describes the lattice structure of solid sodium chloride?
zlopas [31]
It is A , each sodium ion is surrounded by one chloride ion . the explanation is because Chlorine needs one more electron to have a full outer most shell , and sodium has one electron in its outer most shell . 
7 0
3 years ago
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