Question

Solve for the indicate variables. 1) h=vt - 2t^2; for v 2) A=1/2(b1+b2) h; for b1

Answer 1

Solving $h=vt-2t^2$ for v gives $v=\frac{h}{t}+2t$

Solving $A=\frac{1}{2}(b_1+b_2)}$ for b1 gives $b_1=2A-b_2$

Step-by-step explanation:

Given

$h=vt-2t^2$

To solve for v, we have to isolate v on one side of the equation

$h=vt-2t^2\\Adding\ 2t^2\ on\ both\ sides\\h+2t^2=vt-2t^2+2t^2\\h+2t^2=vt\\Dividing\ both\ sides\ by\ t\\\frac{h+2t^2}{t}=\frac{vt}{t}\\v=\frac{h+2t^2}{t}\\v=\frac{h}{t}+\frac{2t^2}{t}\\v=\frac{h}{t}+2t$

Given

$A=\frac{1}{2}(b_1+b_2)}$

To isolate b1 we have to isolate b1

So,

$A=\frac{1}{2}(b_1+b_2)}\\Multiplying\ both\ sides\ by\ 2\\2A=2*\frac{1}{2}(b_1+b_2)}\\2A=b_1+b_2\\Subtracting\ b_2\ from\ both\ sides\\2A-b_2=b_1+b_2-b_2\\b_1=2A-b_2$

Hence,

Solving $h=vt-2t^2$ for v gives $v=\frac{h}{t}+2t$

Solving $A=\frac{1}{2}(b_1+b_2)}$ for b1 gives $b_1=2A-b_2$

Keywords: Variable, Linear equations

Learn more about equations at:

• brainly.com/question/10760452
• brainly.com/question/10882895

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