Answer
For this we use ideal gas equation which is:
P1V1 = P2V2
P1 = 1.10 atm
V1 = 326 ml
P2 = 1.90
V2 = ?
By rearranging the ideal gas equation:
V2 = P1V1 ÷ P2
V2 = 1.10 × 326 ÷1.90
V2 = 358.6 ÷ 1.90
V2 = 188.7 ml
In this question, you are asked to find two condition which was:
1. Same phase at STP( standard temperature and pressure)
2. Different structure and properties
In option 1 and 4 the phase of the element is different. It was solid+gas for option 1 and solid+liquid for option 4. That clearly not fulfills the first condition.
At STP helium is gas but mercury should be liquid, not gas. That means option 3 won't fulfill the 1st condition too.
Option 2 is true since both of them gas and their structure and properties are different. One example of properties is that oxygen doesn't have an odor but ozone has.
C - electric charges have electric fields. imagine a magnet - charge is distributed in space in the same way magnetic field is. if you can imagine how two magnets of the same sign (++/--) repel each other, you can apply that concept to electric charge/field.
opposite
Explanation:
Ionic compounds connects and holds together due to the opposite ionic charges that each element in the compound forms.
Ionic bonds are formed as a result of the electrostatic attraction between oppositely charged ions.
This force is a force of attraction that pulls ions to form compounds.
- Ionic bonds are formed between two species with a large electronegativity difference.
- This is usually a metal and a non-metal in nature.
- The metal loses its electron and becomes positively charged.
- The non-metal due to its electronegativity gains the electrons and becomes negatively charged.
- Attraction between these oppositely charged specie leads to the formation of ionic bonds.
learn more:
Ionic compounds brainly.com/question/6071838
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Answer:
Final temperature of object = 25°C
Explanation:
Given data:
Final temperature of object = ?
Mass of object = 10 g
Specific heat capacity of object = 1 cal/g.°C
Heat content = 50 cal
Initial temperature = 20°C
Solution;
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
Now we will put the values in formula.
50 cal = 10 g × 1 cal/g.°C × (T2 - 20°C)
50 cal/ 10 cal/°C = (T2 - 20°C)
5 °C = (T2 - 20°C)
5°C + 20°C = T2
T2 = 25°C