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Yuliya22 [10]
2 years ago
10

A 0. 22 m aqueous solution of the weak acid ha at 25. 0 °C has a ph of 4. 15. The value of ka for Ha is?

Chemistry
1 answer:
-Dominant- [34]2 years ago
3 0

If 0. 22 m aqueous solution of the weak acid hA at 25. 0 °C has a ph of 4. 15, the value of ka for HA is 2.27 × 10^(-8).

<h3>What is an aqueous solution?</h3>

The aqueous solution is simply defined as something which has been dissolved in water. The aqueous symbol is denoted as (aq).

Given,

pH = 4.15

Concentration of HA = 0.22 M

Firstly, we will calculate the concentration of H+ ion

pH=-log [H+]

4.15 =-log [H+]

= 7.08x 10^{-5}

Secondly we will calculate the value of Ka

for HA is

The equilibrium reaction will be:

HA----- (H+) + (A-)

Given,

Concentration of H+

= Concentration of A-

= 7.08 x 10^{-5} M

The expression of Ka for HA will be,

Ka = [A-] [H+]/[ HA]

= 2.27 × 10^(-8)

Thus we concluded that the value of ka for HA for weak acid HA is 2.27 × 10^(-8).

learn more about aqueous solution or Ka:

brainly.com/question/12481995

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Answer: Potential energy is converted to kinetic energy and back again.

Explanation:At points 1 and 3, the pendulum stops moving, and its mechanical energy is purely potential. At point 2, the pendulum is moving the fastest, and its mechanical energy is purely kinetic. Therefore, as the pendulum moves from point 1 to point 3, its potential energy is first converted to kinetic energy, then back to potential.

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A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm
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Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100

Percent error = \frac{0.1}{63.2}\times 100

Percent error = 0.00158\times 100

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100

Percent error = \frac{0.2}{63.2}\times 100

Percent error = 0.00316\times 100

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100

Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100

Percent error = \frac{(0.5)}{63.2}\times 100

Percent error = 0.00791\times 100

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%




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<h3>What are the factors that affect reaction rate?</h3>

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The factors that affect reaction rate include:

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