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scZoUnD [109]
3 years ago
8

Which pair represents two forms of an element in the same phase at STP but with different structures and different properties?(1

) I2(s) and I2(g) (3) H2(g) and Hg (g)
(2) O2(g) and O3(g) (4) H2O(s) and H2O(l)
Chemistry
2 answers:
SashulF [63]3 years ago
6 0
In this question, you are asked to find two condition which was:
1. Same phase at STP( standard temperature and pressure)
2. Different structure and properties

In option 1 and 4 the phase of the element is different. It was solid+gas for option 1 and solid+liquid for option 4. That clearly not fulfills the first condition. 
At STP helium is gas but mercury should be liquid, not gas. That means option 3 won't fulfill the 1st condition too.

Option 2 is true since both of them gas and their structure and properties are different. One example of properties is that oxygen doesn't have an odor but ozone has.
zmey [24]3 years ago
4 0

Answer;

2) O2(g) and O3(g)

Explanation;

-Considering the above conditions; Same phase at STP, and different structures and different properties;

-The correct choice is; 2) O2(g) and O3(g)

-O2 and O3 are allotropes of oxygen and are both gases at STP and have different properties.

-Ozone and oxygen exist in the same phase at STP; that is both of them are gases at standard temperature and pressure (STP).

- They also have different structures and properties; Ozone is a triatomic molecule consisting of three oxygen atoms, while oxygen is diatomic molecules with two atoms of oxygen. Oxygen is odorless and transparent while ozone has a pungent smell and is bluish colored.

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Karla added green pellets to a container of water before she began watering her lawn. What correctly describes
kvv77 [185]

The correct answer is C. The water is the solvent because the green pellets dissolved in it.

Explanation:

In solutions, the are two substances involved, the solvent and the solute. The solvent is usually a liquid substance; additionally, the solvent dissolves another substance, which is known as the solute. For example, if you dissolve a spoon of salt in a glass of water, the solute is the salt which is the substance dissolved and the solvent is the water because the solute is dissolved in it. According to this, in the case presented the water is the solvent because the green pellets which are the solute dissolve in it.

5 0
4 years ago
In calculating the concentration of [Cu(NH3)4]2+[Cu(NH3)4]2+ from [Cu(H2O)4]2+[Cu(H2O)4]2+, the stepwise formation constants are
tamaranim1 [39]

Answer:

11.1×10^12

Explanation:

β4= K1× K2 × K3 × K4

β4= 1.90×10^4 × 3.90×10^3 × 1.00×10^3 ×1.50×102

β4=11.1×10^12

The overall formation (stability) constant β4= K1× K2 × K3 × K4. Hence the answer.

3 0
4 years ago
What is the quantity of heat (in kJ) associated with cooling 185.5 g of water from 25.60°C to ice at -10.70°C?Heat Capacity of S
Cerrena [4.2K]

Taking into account the definition of calorimetry, sensible heat and latent heat,  the amount of heat required is 37.88 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Sensible heat</h3>

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

  • <u><em>25.60 °C to 0 °C</em></u>

First of all, you should know that the freezing point of water is 0°C. That is, at 0°C, water freezes and turns into ice.

So, you must lower the temperature from 25.60°C (in liquid state) to 0°C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • c= Heat Capacity of Liquid= 4.184 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= 0 °C - 25.60 °C= - 25.6 °C

Replacing:

Q1= 4.184 \frac{J}{gC}× 185.5 g× (- 25.6 °C)

Solving:

<u><em>Q1= -19,868.98 J</em></u>

  • <u><em>Change of state</em></u>

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

n= 185.5 grams× \frac{1mol}{18 grams}= 10.30 moles, where 18 \frac{g}{mol} is the molar mass of water, that is, the amount of mass that a substance contains in one mole.

ΔHfus= 6.01 \frac{kJ}{mol}

Replacing:

Q2= 10.30 moles×6.01 \frac{kJ}{mol}

Solving:

<u><em>Q2=61.903 kJ= 61,903 J</em></u>

  • <u><em>0 °C to -10.70 °C</em></u>

Similar to sensible heat previously calculated, you know:

  • c = Heat Capacity of Solid = 2.092 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= -10.70 °C - 0 °C= -10.70 °C

Replacing:

Q3= 2.092 \frac{J}{gC} × 185.5 g× (-10.70) °C

Solving:

<u><em>Q3= -4,152.3062 J</em></u>

<h3>Total heat required</h3>

The total heat required is calculated as:  

Total heat required= Q1 + Q2 +Q3

Total heat required=-19,868.98 J + 61,903 J -4,152.3062 J

<u><em>Total heat required= 37,881.7138 J= 37.8817138 kJ= 37.88 kJ</em></u>

In summary, the amount of heat required is 37.88 kJ.

Learn more about calorimetry:

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7 0
2 years ago
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