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3 years ago

Which action is characterized of mental illness

Health

2 answers:

ratelena [41]3 years ago

5 0

Answer:

the first one! :)

ryzh [129]3 years ago

3 0

Answer: Option A

Explanation:

Brushing the teeth every hour because one feels dirty is a mental disorder because practically it is not possible that the mouth gets dirty every hour.

Even if someone has a habit of eating, no one brushes the teeth every hour. I is a type of mental disorder in which the person feels that his mouth is dirty and brushes again and again throughout the day.

Rest of the other options are normal and they are normal reaction of the person based on the situation in which they are placed.

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A malnourished child has very low protein in her diet. Which would you expect?.

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Answer:

From a malnourished child that has very low protein in her diet I would expect things such as low absorption along with edema levels increased. Her muscle mass might be low which reduces her strength, has trouble balancing herself and slows the metabolism down. Her cells might not get enough oxygen which might bring her anemia which can additionally cause intense exhaustion.

Explanation:

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2 years ago

Develop a strategy to store food that's left over from dinner?

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1. covering it with a air-tight container or a plastic wrap and storing it in the freezer or fridge ._.

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3 years ago

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A 9-year-old child is having learning difficulties at school. He has brief lapses of awareness with eyelid fluttering that occur

S_A_V [24]

Answer:

B. ethosuximide-valproic acid can be used for absence seizures

Explanation:

The child is suffering from absence seizures and out of above mentioned drugs clonazepam and ethosuximide could be used for the treatment but, clonazepam has depressant effect on central nervous system. On the other hand ethosuximide has less adverse affects, not so sedating and tolerance also does not evolve against its anti-seizure activity. Other medication for this childhood epilepsy include valporic acid and lamotrigine other then ethosuximide, but all these medications have there own side effects with ethosuximide having the fewer.

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3 years ago

Two parents who are heterozygous for type A blood and have sickle cell trait have children.

GuDViN [60]

This question is incomplete, but here is the complete question below.

In humans , blood type is a result of multiple alleles: $I^{A}$ , $I^{B}$ , $i^{o}$ .

A few simple rules of blood type genetics are that:

$I^{A}$ is dominant over $i^{o}$

$I^{B}$ is dominant over $i^{o}$ , and

$I^{A}I^{B}$ are codominant

Two plants who are heterozygous for type A blood and have sickle cell trait have children. Answer the following questions:

a. What is the genotype of the parents?

b. What are the genetic make ups of all the possible gametes they can produce.

c. Complete the dihybrid Punnet square to determine the frequency of the different phenotypes in the offspring.

(NOTE: Consider blood type and normal versus mutant hemoglobin in the various phenotypes.)

Answer:

a) $I^{A}i^{o}AS$

b) $I^{A}A,I^{A}S,i^{o}A,i^{o}S$

c) The dihybrid table is shown in the explanation below and the frequency of the different phenotypes of the offspring are in the ratio of 3:6:3:1:2:1

Explanation:

From the question the genotype of the parents can be determined:

Given that Two parents are heterozygous for type A and have sickle cell trait.

∴ heterozygous for type A will be = $I^{A}i^{o}$ &

heterozygous for having sickle cell traits = AS

Therefore, the traits can be determined the genotype of the parents can be determined as: $I^{A}i^{o}AS$

the genetic make ups of all the possible gametes they can produce can be determined if the parent are self crossed.

If $I^{A}i^{o}AS$ self crossed, we have:

$I^{A}$ $i^{o}$

A $I^{A}A$ $i^{o}A$

S $I^{A}S$ $i^{o}S$

∴ The genetic makeups of all the possible gametes they can produce are:

$I^{A}A$ , $I^{A}S$ , $i^{o}A$ , $i^{o}S$

Below shows the dihybrid Punnet square and the frequency of the different phenotypes in the offspring

I^{A}A I^{A}S i^{o}A i^{o}S

I^{A}A I^{A}I^{A}AA I^{A}I^{A}AS I^{A}i^{o}AA I^{A}i^{o}AS

I^{A}S I^{A}I^{A}AS I^{A}I^{A}SS I^{A}i^{o}AS I^{A}i^{o}SS

i^{o}A I^{A}i^{o}AA I^{A}i^{o}AS i^{o}i^{o}AA i^{o}i^{o}AS

i^{o}S I^{A}i^{o}AS I^{A}i^{o}SS i^{o}i^{o}AS i^{o}i^{o}SS

$\frac{3}{16}$ = 18.75% : Blood type A, normal hemoglobin (normal RBCs) = I^{A}I^{A}AA, I^{A}i^{o}AA, I^{A}i^{o}AA

$\frac{6}{16}$ = 37.5% : Blood type A, normal and mutant hemoglobin (sickle cell trait) = I^{A}I^{A}AS, I^{A}i^{o}AS, I^{A}I^{A}AS, I^{A}i^{o}AS, I^{A}i^{o}AS, I^{A}i^{o}AS

$\frac{3}{16}$ = 18.75% : Blood type A, mutant hemoglobin (sickle cell anemia) = I^{A}I^{A}SS, I^{A}i^{o}SS, I^{A}i^{o}SS

$\frac{1}{16}$ = 6.25% : Blood type O, normal hemoglobin (normal RBCs) = i^{o}i^{o}AA

$\frac{2}{16}$ = 12.5% : Blood type O, Blood type A, normal and mutant hemoglobin (sickle cell trait) = i^{o}i^{o}AA, i^{o}i^{o}AS

$\frac{1}{16}$ = 6.25% : Blood type O, mutant hemoglobin (sickle cell anemia) = i^{o}i^{o}SS

I hope that helps alot!

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4 years ago

6. Explain how fitness testing and test results can affect your overall fitness.

Reptile [31]

Answer: <em>knowing whether or not your body is in shape is an important step in becoming fit. Fitness test results show how you are progressing physically and how you can improve yourself.</em>

hope this helps!^_^

3 0

3 years ago