1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex
3 years ago
15

Which statement is true about a planet’s orbital motion?

Physics
1 answer:
lana66690 [7]3 years ago
3 0

Answer:

Orbital motion results when the object’s forward motion is balanced by a second object’s gravitational pull.

Explanation:

The gravitational force is responsible for the orbital motion of the planet, satellite, artificial satellite, and other heavenly bodies in outer space.

When an object is applied with a velocity that is equal to the velocity of the orbit at that location, the body continues to move forward. And, this motion is balanced by the gravitational pull of the second object.

The orbiting body experience a centripetal force that is equal to the gravitational force of the second object towards the body.

The velocity of the orbit is given by the relation,

                                    V = \sqrt{\frac{GM}{R + h} }

Where

                   V - velocity of the orbit at a height h from the surface

                    R - Radius of the second object

                    G - Gravitational constant

                    h - height from the surface

The body will be in orbital motion when its kinetic motion is balanced by gravitational force.

                         1/2 mV^{2} = GMm/R

Hence, the orbital motion results when the object’s forward motion is balanced by a second object’s gravitational pull.

You might be interested in
a wire carries 15 A. You form it into a singleturn circular loop with magnetic field 80 µT at the loop center. What is the loop
solong [7]
Use the formula B(at the center)= (4 pi * 10^(-7) ) * I (current)   / ( 2 radius)
and you will get the answer that will be 6.

3 0
3 years ago
Read 2 more answers
Which wave causes the medium to vibrate only in a direction parallel to the wave’s motion?
vivado [14]
None of above/D (but I'm not very sure)
5 0
4 years ago
Read 2 more answers
What is the x-component of a vector with a magnitude of 115 km at an angle of 22°?
ruslelena [56]

The x-component of a vector are < 106.6, 43.07 >

Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.

If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,

v = ||v|| cos θi + ||v|| sin θj

 =  < ||v|| cos θ , ||v|| sin θ >

Magnitude p = 115 km

Angle = 22°

p = ||p|| < cos θ, sin θ >

p = 115 < cos 22°, sin 22° >

p = 115 < 0.927, 0.3746 >

p = < 106.6, 43.07 >

Therefore,  the x-component of a vector are < 106.6, 43.07 >

Learn more about vectors here:

brainly.com/question/8043832

#SPJ1

4 0
2 years ago
What does this mean Atoms and elements are the basic back bone of the universe .
il63 [147K]
It means every thing is made out of Atoms and some things are element componds so elements are the "backbone" of the compounds.
8 0
3 years ago
A potter's wheel is rotating around a vertical axis through its center at a frequency of 2.0 rev/srev/s . The wheel can be consi
vagabundo [1.1K]

Answer:1.7 rev/s

Explanation:

Given

Frequency of wheel N_1=2\ rev/s

angular speed \omega_1=2\pi N_1=4\pi\  rad/s

mass of wheel m_1=4.5\ kg

diameter of wheel d_1=0.30\ m=30\ cm

radius of wheel r_1=\frac{d_1}{2}=\frac{30}{2}=15\ cm

mass of clay m_2=2.8\ kg

the radius of the chunk of clay r_2=8\ cm

Moment of inertia of Wheel

I_1=\dfrac{m_1r_1^2}{2}=\dfrac{4.5\times 15^2}{2}\ kg-cm^2

Combined moment of inertia of wheel and clay chunk

I_2=\dfrac{m_1r_1^2}{2}+\dfrac{m_2r_2^2}{2}=\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2}\ kg-cm^2

Conserving angular momentum

\Rightarrow I_1\omega_1=I_2\omega_2\\\Rightarrow \dfrac{4.5\times 15^2}{2}\cdot 4\pi=(\dfrac{4.5\times 15^2}{2}+\dfrac{2.8\times 8^2}{2})\omega_2\\\\\Rightarrow \omega _2=\dfrac{4\pi }{1+\dfrac{2.8}{4.5}\times (\dfrac{8}{15})^2}=\dfrac{4\pi}{1+0.1769}=0.849\times 4\pi

Common frequency of wheel and chunk of clay is

\Rightarrow N_2=\dfrac{4\pi \times 0.849}{2\pi}=1.698\approx 1.7\ rev/s

5 0
3 years ago
Other questions:
  • A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity acting on the block (the weight
    14·1 answer
  • New York’s Finger Lakes were formed by the same process as the Great Lakes.
    14·2 answers
  • When light is scattered while spreading out through the atmosphere, the light rays A) converge and follow the same direction. El
    10·2 answers
  • At summer camp, the swimming course runs the length (L) of a small lake. To determine the length of the course, the camp counsel
    6·1 answer
  • A satellite is always being pulled by gravity.truefalse
    7·1 answer
  • Car decelerates uniformly and comes to a stop after 10 s. The car's average velocity during deceleration was 50 km/h. What was t
    15·1 answer
  • I need help!! Due at midnight.
    6·1 answer
  • What is one source error associated with self-report inventories, and what is one of its solutions?
    7·2 answers
  • A 1. 18 kg gold cube hangs at the end of a 4. 00 m long string. Rhogold = 19. 3 × 103 kg/m3; rhomercury = 13. 6 × 103 kg/m3. Whe
    10·1 answer
  • four objects are situated along the y axis as follows: a 2.00kg object is at +3.00m. a 3.00kg object is at +2.50m, a 2.50kg obje
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!