Where danger is and how to avoid it as well as to locate other whales
Added potential energy = (mass) x (gravity) x (height)
or
Added potential energy = (weight) x (added height)
If you need to lift a 15N box 3m straight up, you have to increase its potential energy by (15 N) x (3 m) = 45 Joules .
Where is that added potential energy supposed to come from ? You could use an electric winch, a steam engine, a gasoline-powered motor, thousands of hamsters running on little treadmills that are are connected to the main pulley somehow, or your own arm muscles. But howEVER you do it, you have to provide <em>45 Joules</em> of WORK in order to increase the potential energy of the box by just that much.
Answer:
T = 3.475 s
Time period is independent from mass
Explanation:
- To reduce the human error in taking any measurements we take multiple N number of readings. Then sum up all the readings and divide by N to find an average. The error between each individual reading and the actual reading is reduced by repetition.
- We use the plot of T^2 against L to form a linear relationship between two variables. We square the entire the equation for linearize the equation.
- Given, L = 3 m . The time period is approximated by a pendulum expression given as:
T = 2*pi*sqrt ( L / g )
Where, g is the gravitational acceleration 9.81 m/s^2
- Then we have:
T = 2*pi*sqrt ( 3 / 9.81 )
T = 3.475 s
- From above expression we see that time period is independent from the mass at the end of the string but a function of pendulum geometry and kinetics.
Take 10m/s^2 for the gravitational acceleration, as we know this is a free fall, we can use the equation: d=1/2*g*t^2
Substitute g=10m/s^2, t=5s, d=125m
Answer:
Explanation:
<u>Net Force And Acceleration
</u>
The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by
The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N
The components of the first force are
The components of the second force are
The net force is
The magnitude of the net force is
The acceleration has a magnitude of
The direction of the acceleration is the same as the net force:
