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postnew [5]
3 years ago
9

Two stones, one of mass m and the other of mass 2m, are thrown directly upward with the same velocity at the same time from grou

nd level and feel no air resistance. Which statement about these stones is true?
a. The heavier stone will go twice as high as the lighter one because it initially had twice as much kinetic energy.
b. Both stones will reach the same height because they initially had the same amount of kinetic energy.
c. At their highest point, both stones will have the same gravitational potential energy because they reach the same height.
d. At Its highest point, the heavier stone will have twice as much gravitational potential energy as the lighter one because it is twice as heavy.
e. The lighter stone will reach its maximum height sooner than the heavier one.
Physics
1 answer:
brilliants [131]3 years ago
8 0

Answer:

c.  At their highest point, both stones will have the same gravitational potential energy because they reach the same height.

Explanation:

The above statement is true going by the fact that, the gravitational potential energy of both stones is a function of its mass (weight) as well as the height at which it reach. <em>Despite the fact that, both stones has different weights, it would reach different heights. At their various maximum height, the will have same potential energy.</em>

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152 pounds

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4 0
3 years ago
a rocket, initially at rest, is fired vertically with a net upward acceleration of 12 m/s2 . at an altitude of 0.50 km, the engi
kobusy [5.1K]

The rocket travelled a maximum height at 1.0102 km.

Given,

The acceleration of a rocket (a) = 12 m/s²

The altitude of the rocket (s) =  0.50 km = 0.5×10³m

The maximum height of the rocket (h) = ?

Solution,

A rocket is a spacecraft, aircraft, vehicle or projectile that obtains thrust from a rocket engine.

The rate of change of the velocity of an object with respect to time is known as acceleration. It is denoted by (a).i.e. unit is m/s²

(a) = Δv/Δt

Where , Δv is change in velocity and Δt is change in time.

The rate of change in position with respect to time is known as velocity. i.e. Its unit is m/s.

(v)= Δx/Δt

Where,Δx is the change in position and Δt is change in time & v is velocity.

Therefore we know the equation of motion is written as,

v² = u² +2as

Where, v  is final velocity , u is initial velocity , a is acceleration and s is altitude of the rocket.

Then putting the value ,

v² = 0 + ( 2× 10 × 0.5×10³)m/s

v² = \sqrt{10000} m/s

v = 100 m/s

Therefore, at altitude of 0.50 km the initial velocity of rocket (u) will be 100 m/s, final velocity v become zero and under free falling the acceleration will be taken (-g) then equation of motion can be given as ,

v² = u² - 2(g)h

h = (v²- u² ) / 2g

h = 10,000/2×9.8

h = 510.2 m

So that the rocket travelled the maximum height ,

(h)= (0.5 km + 510.2m)

(h) = 1.0102 km

Hence, the rocket travelled at the maximum height h is 1.0102 km

To know more about acceleration

brainly.com/question/15135960

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4 0
1 year ago
Find the measure of angle x in the figure below:
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Answer:

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4 0
2 years ago
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expeople1 [14]

Answer:

Option 3

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O Option C is NEGATIVELY CHARGED, meaning it has GAINED ELECTRONS resulting in a GREATER number of ELECTRONS than PROTONS.

8 0
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