Each curve completes one loop over the interval
. Find the intersections of the curves within this interval.
The region of interest has an area given by the double integral
equivalent to the single integral
which evaluates to
.
For the 11 the first one is x = 4y and for the 2 one it will be x=−6−2y
Larger by 3 means that the legnths of the sides are larger by 3 times
so we have a cube that has area of 400
surface area=legnth times width times 6 since it is a cube and legnth=width
so
SA=w^2 times 6
6w^2=400
divide by 6
w^2=200/3
square root both sides
w=√(200/3)
so w is 3 times larger
(3w)^2 times 6 is new area
w=√(200/3)
(3√(200/3))^2 times 6=9(200/3) times 6=600 times 6=3600
answer is 3600 ml^2
Answer:15 miles
Step-by-step explanation: 5 times 3
