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devlian [24]
3 years ago
6

How to convert 23.125 to binary (Hex) using the double - precision representation

Computers and Technology
1 answer:
Svet_ta [14]3 years ago
6 0

Answer:-

(10111.001)₂

Explanation:

To convert a decimal number to a binary number we have to constantly divide the decimal number by 2 till the decimal number becomes zero and the binary number is writing the remainders in reverse order of obtaining them on each division.

Hence the binary number is 10111.001

To convert binary to hexa decimal we to make a group 4 binary bits starting from the decimal and moving outwards if the last group is not of 4 then add respective 0's and write the corresponding hexa decimal number.

<u>0001</u>  <u>0111</u> . <u>0010</u>

   1        7         2

Hence the hexadecimal number is 17.2

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What is the output of this code? import java.util.HashSet; class A { public static void main(String[ ] args) { HashSet set = new
kompoz [17]

Answer:

The code will give an error that is "At least one public class is required in main file".

Explanation:

In the given code if we do not use the public access modifier to the class. It will give an error so, the correct code to this question as follows:

Program:

import java.util.HashSet; //import package

public class A  //define class as public.

{

   public static void main(String[ ] args) //define main method.

   {

       HashSet set = new HashSet(); //creating hashset object.

       set.add("A"); //add alphabet in hashset

       set.add("B"); //add alphabet in hashset

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}

Output:

Size of HashSet is : 3

Explanation of the program:  

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3 years ago
Write a function that takes as input a single integer parameter n and computes the nth Fibonacci Sequence number. The Fibonacci
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Answer:

Following are the code to this question:

def Fibonacci(n):#defining a method Fibonacci that accept a parameter

   a = 1#defining a variable a that holds a value 1

   b = 1#defining a variable b that holds a value 1

   if n <= 0:# Use if to check n value

       print("invalid number")#print message

   elif n == 2:#defining elif that check n equal to 2

        return 1#return 1

   else:#defining else block

       print(a)#print value of a

       print(b)#print value of b

       for i in range(2,n):#defining for loop to calculate series

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           a = b # interchange value

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1

1

2

3

5

8

13

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Explanation:

In the above-given program code, a method "Fibonacci" is defined, which holds a value "n" in its parameter, and inside the method two-variable "a and b" is defined, that holds a value "1".

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  • In the else block, it will calculate the Fibonacci series and print its value.
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Hello <span>Alexkalhor5415

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