Someone please help as soon as possible

6x+7y=4x+4y6x+7y=4x+4y6, x, plus, 7, y, equals, 4, x, plus, 4, y Complete the missing value in the solution to the equation. (((

Dmitrij [34]

Answer:

<h3>The missing value in the given solution is x=6</h3><h3>Therefore the solution is (6,-4)</h3>

Step-by-step explanation:

Given equation is $6x+7y=4x+4y\hfill (1)$

<h3>To find the missing value in the solution to the equation :</h3>

Let missing value in the solution be x
Then the solution of the given equation is (x,-4)

Substitute the value of y=-4 in the given equation (1) we get

$6x+7(-4)=4x+4(-4)$

$6x-28=4x-16$

$6x-28-(4x-16)=4x-16-(4x-16)$

$6x-28-4x+16=4x-16-4x+16$ ( adding the like terms )

$2x-12=0$

$2x=12$

$x=\frac{12}{2}$

Therefore x=6

<h3>Therefore the missing value in the given solution is x=6</h3><h3>Therefore the solution is (6,-4)</h3>

8 0

2 years ago

If Figure X is similar to Figure Y, and Figure Y is similar to Figure Z, can you conclude that Figure X is similar to Figure Z?

nexus9112 [7]

Yes, transitive property of equality

8 0

2 years ago

URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(c) $\log_2(\dfrac{64}{8})=3$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

5 0

2 years ago

Lauren has an above-ground pool. to keep the pool's skimmer working well, the water level must be 4 inches from the top of the p

Ostrovityanka [42]

1885.5 m^3 of water will fill the container.

To find how many cubic feet of water will it contain:

Given -

Lauren has an above-ground swimming pool.
The water level in the pool must be 4 inches above the pool's surface in order for the skimmer to function properly.
π = 3.14

The pool comprises a 12-foot-radius cylinder with a height of 4.5 feet.

Height of pool = 4.5 ft
Radius of pool = 12 ft
The height of the water is 4 inches below the pool top
12 inches make 1 ft
4 inches = 4/12 ft = 0.33 ft
Therefore, height of water = 4.5 - 0.33 = 4.17 ft

The volume of the water in this section of the cylinder will be equal to the volume of the cylinder formed.

The volume of the cylinder formed by the water = volume of water = $\pi r^{2} h$
volume = 3.14 x $12^{2}$ x 4.17 = 1885.5 m^3 of water

Therefore, 1885.5 m^3 of water will fill the container.

Know more about volumes here:

brainly.com/question/1972490

#SPJ4

The complete question is given below:

Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the pool. When the pool is filled to this recommended level, approximately how many cubic feet of water will it contain? Use π = 3.14

A cylinder with a radius of 12 feet and a height of 4.5 feet.

7 0

1 year ago

Question 30. How do you set up the equation?

Bas_tet [7]

140 pounds * 6 feet = 112 pounds * x feet

x feet = (140 * 6) / 112

x = 7.5 feet

7 0

2 years ago