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3 years ago

The function h(x)=x^2+3 and g(x)=x^2-6 if g(x)=h(x)+k what is the value of k

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

8 0

Answer:

hello : k = - 9

Step-by-step explanation:

h(x) =x²+3 and g(x) = x² - 6.....(*)

g(x) = x² +3 + k.....(**)

by (*) and (**) : 3+k = -6

3+k - 3 = - 6 - 3

k = - 9

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A line passes through the point (-1, -7) and has a slope of -8.

mr_godi [17]

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Answer:

y = -8x -15

Step-by-step explanation:

It can be useful to start with the point-slope form when you are given a point and a slope.

y -k = m(x -h) . . . . . line with slope m through point (h, k)

For the given line, this equation is ...

y +7 = -8(x +1)

y = -8x -8 -7 . . . . eliminate parentheses, subtract 7

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2

svetlana [45]

Answer:

The equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1$ .

Step-by-step explanation:

Given

The equation of ellipsoid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1$

The equation of tangent plane at the point $\left(x_0,y_0,z_0\right)$

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1$ ( Given)

The equation of hyperboloid

$\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1$

F(x,y,z)= $\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}$

$F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}$

$(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)$

The equation of tangent plane at point $\left(x_0,y_0,z_0\right)$

$\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0$

The equation of tangent plane to the hyperboloid

$\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0$

The equation of tangent plane

$2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2$

Hence, the required equation of tangent plane to the hyperboloid

$\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0$

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2 years ago

Answer quick Question 2 of 5

Anettt [7]

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Step-by-step explanation:

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2 years ago

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ValentinkaMS [17]

The two highlighted rows show that for the same amount of blue, Purple #1 uses more red than Purple #2.

This means that Purple #1 is a redder shade of purple than Purple #2.

Purple #2 is a bluer shade of purple than Purple #1.

Step-by-step explanation:

The two highlighted rows show that for the same amount of blue, Purple #1 uses more red than Purple #2.

Making blue's quantity as 3 parts for purple #1 implies red part becomes 1.5 to maintain the ratio 1:2

Purple #1 has 1/3 parts red and 2/3 parts blue. Purple #2 has 1/4th part red and 3/4th part blue.

Hence, Purple #1 is a redder shade of purple than Purple #2.

From the above explanation, Purple #2 is a bluer shade of purple than Purple #1.

Sure hopes this helps you :)

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