3 years ago

What is the solution set of the quadratic equation - 2(2x-7)^2 = - 8

Mathematics

1 answer:

barxatty [35]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

Given

- 2(2x - 7)² = - 8 ( divide both sides by - 2 )

(2x - 7)² = 4 ( take the square root of both sides )

2x - 7 = ± $\sqrt{4}$ = ± 2 ( add 7 to both sides )

2x = 7 ± 2

2x = 7 - 2 = 5 or 2x = 7 + 2 = 9 ( divide both sides by 2 )

x = $\frac{5}{2}$

x = $\frac{9}{2}$

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What is the solution set of the quadratic equation - 2(2x-7)^2 = - 8​​

What is the solution set of the quadratic equation - 2(2x-7)^2 = - 8