Question

Read the chemical equation.

Answer 1

Answer: The volume of ammonia produced is 0.8 L

Explanation:

At STP:

1 mole of a gas occupies 22.4 L of volume

We are given:

Volume of nitrogen gas = 1.2 L

For the given chemical reaction:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

As, nitrogen gas is given in excess, it is considered as excess reagent. And, hydrogen gas is considered as the limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

(3 × 22.4) L of hydrogen gas produces (2 × 22.4) L of ammonia

So, 1.2 L of hydrogen gas will produce $\frac{(2\times 22.4)}{(3\times 22.4)}\times 1.2=0.8L$ of ammonia

Hence, the volume of ammonia produced is 0.8 L

Answer 2

Answer : The volume of $NH_3$ produced is, 0.8 liters

Explanation :

The balanced chemical reaction will be,

$N_2+3H_2\rightarrow 2NH_3$

The mole ratio of nitrogen, hydrogen and ammonia are 1 : 3 : 2.

According to the Avogadro's Law, the volume is directly proportional to the number of moles of the gas at constant pressure and temperature.

$V\propto n$   (At constant temperature and pressure)

or,

$\frac{V_1}{V_2}=\frac{n_1}{n_1}$

where,

$V_1$ = volume of hydrogen = 1.2 L

$V_2$ = volume of ammonia = ?

$n_1$ = moles of hydrogen = 3 mole

$n_2$ = moles of ammonia = 2 mole

Now put all the given values in the above formula, we get the volume of ammonia.

$\frac{1.2L}{V_2}=\frac{3mole}{2mole}$

$V_2=0.8L$

Therefore, the volume of $NH_3$ produced is, 0.8 liters