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blagie [28]
3 years ago
8

In subsequent experiments you determine that the compound is iron (II) chloride. Which of the following properties would you als

o expect iron (II) chloride to demonstrate?a. soluble in a nonpolar solvents b. Conducts electricity when dissolved in water c. Hard and brittled. Does not conduct electricity when moltene. Low melting point, around 40 °C
Chemistry
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

b. Conducts electricity when dissolved in water

Explanation:

Iron(II) chloride, is the chemical compound with formula FeCl2.

It is a solid with a high melting point of about 677 degree Celsius or 950 K when in anhydrous form but have lower melting point in hydrated form.

The compound is often off-white. FeCl2 crystallizes from water as the greenish tetrahydrate, which is the form that is most commonly encountered in the laboratory.

There is also a dihydrate. The compound is highly soluble in water, giving pale green solutions.

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viktelen [127]

Answer:

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Explanation:

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4 0
3 years ago
Which of the following is NOT the same as 13.6 milliliters?
rjkz [21]
HI There! 

Which of the following is NOT the same as 13.6 milliliters?- 0.0136 dkL
- 0.0136 L
- 0.136 dL

Answer:<span>0.0136 dkL</span>
4 0
3 years ago
A photon with 2.3 eV of energy can eject an electron from potassium. What is the corresponding wavelength of this type of light?
Ira Lisetskai [31]

Answer:

\lambda=540.16\ nm

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy = 2.3\times 1.60\times 10^{-19}\ J=3.68\times 10^{-19}\ J

Considering

Energy=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light being bombarded

Thus,  

3.68\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\frac{3.68}{10^{19}}=\frac{19.878}{10^{26}\lambda}

3.68\times \:10^{26}\lambda=1.9878\times 10^{20}

\lambda=5.40163\times 10^{-7}\ m=540.16\times 10^{-9}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=540.16\ nm

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4 years ago
What is the answer I need help bad
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