The second one, I could be mistaken though
It has 9 protons, 9 electrons and 10 neutrons.
When the use of significant figures and rounding up is applied correctly the mass of the mixture will be 80.5 g.
In cases of addition or subtraction, only the last significant figure of every number is taken into account.
In 30.05, this is 5, in the hundredths. When we look at 50.0, the last significant figure is 0, and it is in the tenths. And in 0.4006, the last significant figure is 6, in the ten thousandths. Of these three, the 0 from 50.0 is in the leftmost position, which means that the last significant figure of the result needs to be in the same position (in the tenths).
Moving onto the actual algebraic operation:
30.05 g + 50.0 g + 0.4006 = 80.4506 g
As we established, the last significant figure should be in the tenths, and we will have to round up 4 to 5 (trailing numbers are greater than 0), which means that the resulting mass will be 80.5 g.
You can learn more about significant figures here:
brainly.com/question/14804345
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The given sentence is part of a longer question.
I found this question with the same sentence. So, I will help you using this question:
For the reaction N2O4<span>(g) ⇄ 2NO</span>2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm<span>). If </span>Kp = 0.15, which statement is true of the reaction mixture before
any reaction occurs?
(a) Q = K<span>; The reaction </span>is at equilibrium.
(b) Q < K<span>;
The reaction </span>will proceed to
the right.
(c) Q > K<span>; The reaction </span>will proceed to the left.
The answer is the option (c) Q > K<span>; The reaction will proceed to the </span>left,
since Qp<span> = </span>1<span>, and 1 > 0.15.</span>
Explanation:
Kp is the equilibrium constant in term of the partial pressures of the gases.
Q is the reaction quotient. It is a measure of the progress of a chemical reaction.
The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.
At equilibrium both Kp and Q are equal. Q = Kp
If Q < Kp then the reaction will go to the right (forward reaction) trying to reach the equilibrium,
If Q > Kp then the reaction will go to the left (reverse reaction) trying to reach the equilibrium.
Here, the state is that both pressures are 1 atm, so Q = (1)^2 / 1 = 1.
Since, Q = 1 and Kp = 0.15, Q > Kp and the reaction will proceed to the left.
The atomic number of Nickle is 28, so its electronic configuration in ground state is,
Ni = 28 e⁻ = 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d⁸
So, when Nickle looses two electrons it will attain +2 charge, remaining with 26 electrons as,
Ni⁺² = 26 e⁻ = 1s², 2s², 2p⁶, 3s², 3p⁶, 3d⁸
Ni looses electrons from 4s shell instead instead of 3d shell because the 4s shell electrons are at larger distance as compared to 3d, hence, felting less nuclear charge and easily lost.
