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yuradex [85]
4 years ago
10

Zn(s)+2 HCl(aq)→ZnCl2(aq)+H2(g)

Chemistry
1 answer:
Veronika [31]4 years ago
8 0

The answer is 300,400

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Given the following equation: 8Fe+S8=8FeS
maxonik [38]

Answer:

a. 2954g of FeS

b. 1143g of FeS

Explanation:

Based on the reaction:

8 Fe + S₈ → 8 FeS

<em>8 moles of Fe reacts with 1 mole of S₈ to produce 8 moles of FeS</em>

<em />

a. 4.2mol sulfur produce:

4.2mol S₈ × ( 8 mol FeS / 1 mol S₈) = <em>33.6mol FeS</em>. As molar mass of FeS is 87.92g/mol, mass is:

33.6mol FeS × ( 87.92g / 1 mol FeS) = <em>2954g of FeS</em>

<em />

b. 13mol Fe produce:

13mol Fe × ( 8 mol FeS / 8 mol Fe) = <em>13mol FeS</em>. In mass:

13 mol FeS × ( 87.92g / 1 mol FeS) = <em>1143g of FeS</em>

5 0
3 years ago
Most of the volume of a gas is
Vesna [10]

Answer:

One mole of any gas has a volume of 24 dm3 or 24,000 cm3 at rtp (room temperature and pressure).

Explanation:

3 0
3 years ago
Salt compounds are composed of ions that form a tightly packed and ordered network, which is called a crystal lattice, and it is
Genrish500 [490]
<span>Salt compounds are composed of ions that form a tightly packed and ordered network, which is called a crystal lattice. It is held together by electrostatic forces known as ionic bonding. Ionic bonding refers to the chemical bond between two oppositely charged ions - a cation and an anion. This type of bond forms when there is a large electronegativity difference between two atoms. </span>
7 0
3 years ago
Calculate the [OH-] and the pH of a solution with an [H+= .00083 M at 25 degrees
sesenic [268]
<h3>Answer:</h3>

1.2 × 10^-11 M

<h3>Explanation:</h3>

<u>We are given;</u>

Concentration of Hydrogen ions [H⁺] as 0.00083 M

<u>We are required to calculate the concentration of [OH⁻]</u>

We know that;

pH = - log [H⁺]

POH = -log[OH⁻]

Also, pH + pOH = 14

With the concentration of H⁺ we can calculate the pH

pH = -log 0.00083 M

    = 3.08

But; pH + pOH = 14

Therefore; pOH = 14 - pH

                           = 14 - 3.08

                          = 10.92

But, pOH = -log[OH⁻]

Therefore; [OH] = -Antilog(pOH)

Hence; [OH⁻] = Antilog -10.92

                     = 1.2 × 10^-11 M

Therefore, [OH⁻] is 1.2 × 10^-11 M

6 0
3 years ago
A 20 gram piece of metal is added to a sample of 100 grams of water inside a calorimeter. If the metal is at a temperature of -5
telo118 [61]

Answer:

The energy gained by the metal equals the energy lost by the water.

<em>Explanation: </em>

The metal is colder than the water, so heat energy will flow rom the water to the metal.  

According to the <em>Law of Conservation of Energy</em>, energy cannot be destroyed or created.  

If the metal gains a certain amount energy, the water must lose the same amount.

We <em>don’t know</em> what the final temperature of the water will be, because we don’t know the specific heat capacity of the metal. However, there is more water than metal and metals don’t have small heat capacities, so the temperature of the water won’t drop very much (maybe 1 °C).

So, the temperature increase of the metal will be much bigger than the temperature decrease of the water.

Certainly, the water will <em>not</em> warn up when the cold metal is added to it.

6 0
3 years ago
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