Answer:
9b) -8 = y
9a) 72° = <em>m</em>∠<em>ABC</em>
Step-by-step explanation:
Since you have an angle trisector, in this case, <em>m</em>∠<em>CBE</em><em> </em>≅ <em>m</em>∠<em>DBA,</em><em> </em>therefore you <em>set</em><em> </em><em>x</em><em> </em>equal to 8, plus, according to Morley's Trisector Theorem, all three angles form an equilateral triangle, so <em>m</em>∠<em>BOC</em><em> </em>also has to equal 24°:

Then, <em>m</em>∠<em>ABC</em><em> </em>comes from multiplying 3 by 24 [three <em>twenty-</em><em>four</em>'s], which results in 72°.
I am joyous to assist you anytime.
Answer:
x = 3
Step-by-step explanation:
The midsegment is half the sum of the parallel bases, that is
(3x + 3 + 4x + 2) = 13
(7x + 5) = 13 ( multiply both sides by 2 )
7x + 5 = 26 ( subtract 5 from both sides )
7x = 21 ( divide both sides by 7 )
x = 3
Answer:
1. p->q
2. p<->q
3. :.p^q
Step-by-step explanation:
I hope this will help you
W=14 that’s because 360-80=280 then you have to divide that by 20. And you get 14 weeks.
Answer:
Use SAS to show that triangles PRQ and PRS are congruent.
Step-by-step explanation:
Since PR bisects angle QPS, angles QPR and SPR are congruent. By reflexive property of congruence, PR is congruent to itself. Since PQ is congruent to PS, we can use SAS to show that the two triangles are congruent. By CPCTC, QR is congruent to SR.