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agasfer [191]
3 years ago
11

How do I write 2\5, 1.4, 1\3, and 0.5 from least to greatest?

Mathematics
2 answers:
Ymorist [56]3 years ago
5 0
The answer is 1/3 2/5 0.5 1/4
Daniel [21]3 years ago
4 0
U need a calculator for this 2 divided by 5 is 0.4 and 1 divided by 3  is 0.3
so from least to greatest is 1/3,2/5,0.5,1.4
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Solve for x . 8x-3 &amp; 4x+3 <br> 8x-3+4x+3=180<br> ?x+_=180
STALIN [3.7K]

Answer:

x = 15

Step-by-step explanation:

the 2 angles are a linear pair and sum to 180° that is

8x - 3 + 4x + 3 = 180

12x = 180 ( divide both sides by 12 )

x = 15

6 0
2 years ago
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What does the point (1,8) mean in this situation?
sesenic [268]

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▹ Answer

<em>There are 8 chocolate chips in one pancake.</em>

▹ Step-by-Step Explanation

The x is labeled as Number of Pancakes.

The y is labeled as Number of Chocolate Chips

Therefore, the 1 represents the pancakes and the 8 represents the amount of chocolate chips per pancake. This would be stated as:

There are 8 chocolate chips in one pancake.

Hope this helps!

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7 0
3 years ago
Read 2 more answers
Use the method of your choice to factor 8m^3−343 completely.
devlian [24]
52m(-872)=92.28763m
The method would be the power of m with 92=92.28763
7 0
3 years ago
What is the equation of the axis of symmetry
Marina86 [1]
The line of symmetry is 1
4 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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