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kumpel [21]
2 years ago
7

Six times the quotient of twenty-one and three is forty-two.

Mathematics
1 answer:
maw [93]2 years ago
6 0

Answer:6*(21/3)=42

Step-by-step explanation:

You might be interested in
Factorise :x^2y^2-16​
Lyrx [107]

Answer:

(xy - 4)(xy + 4).

Step-by-step explanation:

The is the difference of 2 squares.  

a^2 - b^2 = (a - b)(a + b: so we have:

x^2y^2 - 16​ = (xy - 4)(xy + 4)

5 0
3 years ago
A function is expressed by the equation y=0.3x−6. For what value of the independent variable will the value of the function be e
Anna11 [10]

Answer:

0; 10; 20

Step-by-step explanation:

x is the independent variable

y is the dependent variable

y is dependent on x

a) For what value of the independent variable will the value of the function be equal to −6

y=0.3x−6

-6 = 0.3x-6

0=0.3x

x = 0

Therefore, if the independent variable is 0, the value of the function will be -6.

b) For what value of the independent variable will the value of the function be equal to −3

y=0.3x−6

-3 = 0.3x-6

0.3x = -3+6

0.3x = 3

x = 3/0.3

x = 10

Therefore, if the independent variable is 10, the value of the function will be -3.

c) For what value of the independent variable will the value of the function be equal to 0.

y=0.3x−6

0=0.3x-6

6 = 0.3x

x = 6/0.3

x = 20

Therefore, if the independent variable is 20, the value of the function will be 0.

7 0
2 years ago
I’m lost again can somebody help asap ??
serious [3.7K]
Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(5^{- 5} \times 2^8 \times 1 \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(2^8 \times 1 \times \dfrac{1}{5^5} \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{2^8 \times 1}{5^5} \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(1 \times \dfrac{256}{3125} \Bigg)^{- 2}}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \Bigg(\dfrac{3125}{256} \Bigg)^2}

\mathbf{2^{28} \times \Bigg(\dfrac{5^{- 2}}{2^3} \Bigg)^4 \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \Bigg(\dfrac{1}{2^3 \times 5^2} \Bigg)^4 \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(2^3 \times 5^2)^4} \Bigg) \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \Bigg(\dfrac{1^4}{(5^2)^4 \times (2^3)^4} \Bigg) \times \dfrac{3125^2}{256^2}}

\mathbf{2^{28} \times \dfrac{1}{2^{12} \times 5^8} \times \dfrac{3125^2}{256^2}}

\mathbf{\dfrac{3125^2 \times 1 \times 2^{28}}{256^2 \times 5^8 \times 2^{12}}}

\mathbf{\dfrac{2^{(28 - 12)} \times 3125^2}{256^2 \times 5^8}}

\mathbf{\dfrac{2^{16} \times 3125^2}{256^2 \times 5^8}}

\mathbf{\dfrac{2^{16} \times (5^5)^2}{(2^8)^2 \times 5^8}}

\mathbf{\dfrac{2^{16} \times 5^{10}}{2^{16} \times 5^8}}

\mathbf{\dfrac{2^{16} \times 5^{10 - 8}}{2^{16}}}

\mathbf{\dfrac{5^{10 - 8}}{1}}

\mathbf{\therefore \quad 5^2}

\mathbf{\therefore \quad 25}

\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}

Hope it helps.
7 0
3 years ago
Devon’s free-throw average for basketball is 60%. Predict how many times in the next 50 tries he will make a free throw. 
Maru [420]

Answer:

30

Step-by-step explanation:

3 0
2 years ago
Please help me with this
NemiM [27]
What's up? this is C. the base fee, $15 does not change. so we can eliminate A and B. the rate, $8 per hour, will start rising when more hours are spent mowing. this is the same as saying "8h" so, it has to be C.

best of luck with your studies
8 0
2 years ago
Read 2 more answers
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