Answer:
4.5 moles
Explanation:
One mole is equal to 6.022 x 10^23 atoms
2.71 x 10^24 atoms * 1 mol/ 6.022 x 10^23 atoms = 4.5 moles
If they didn't, they wouldn't be able to communicate their findings effectively. An international language is especially important for elements because many elements have similar properties (e.g. some of the transition metals).
When you calculate the first two numbers in 493×10
73.606 °C is the freezing point of the solution made with with 1.31 mol of CHCl3 in 530.0 g of CCl4.
Explanation:
Data given:
number of moles of CHCl3 = 1.31 moles
mass of solvent CHCl3 = 530 grams or 0.53 kg
Kf = 29.8 degrees C/m
freezing point of pure solvent or CCl4 = -22.9 degrees
freezing point = ?
The formula used to calculate the freezing point of the mixture is
ΔT = iKf.m
m= molality
molality = 
putting the value in the equation:
molality= 
= 2.47 M
Putting the values in freezing point equation
ΔT = 1.31 x 29.8 x 2.47
ΔT = 73.606 degrees