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FinnZ [79.3K]
2 years ago
8

The Surface Pressure at Leh, Ladakh is 800 mb. Now, assuming that Leh is at an altitude of 3500 m and every 100 m increase in he

ight with respect to sea level corresponds to 10 mb pressure, What is the Sea Level Pressure at Leh
Physics
1 answer:
Basile [38]2 years ago
8 0

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

<h3> Sea level pressure</h3>

Question Parameters:

Ladakh is 800 mb.

<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level <em>pressure</em> we need to add,

Ps=800+350

Ps= 1150 mb

For more information on Pressure visit

brainly.com/question/25688500

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The voltage across a membrane forming a cell wall is 72.7 mV and the membrane is 9.22 nm thick. What is the magnitude of the ele
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Answer:

The  magnitude of the  electric field intensity is  E =  7.89  *10^{6} \ V/m

Explanation:

From the question we are told that

    The  voltage is  \epsilon     =  72.7 \ mV  =  72.7 *10^{-3}  V

    The  thickness of the membrane is  t =  9.22 \ nm  =  9.22 *10^{-9} \ m

     

Generally the electric field intensity is mathematically represented as

                E =  \frac{\epsilon }{t}

 substituting values

                E =  \frac{72.7 *10^{-3} }{9.22 *10^{-9}}

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8 0
3 years ago
A stone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. Remembering
Black_prince [1.1K]
<h2>Answer: 469 feet</h2>

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y is the height of the stone at 6s (the value we want to find)

y_{o}=925ft is the initial height of the stone

V_{o}=20ft/s is the initial velocity of the stone

t=6s is the time  at which we need to find the height

g=32ft/s^{2} is the acceleration due to gravity

Having this clear, let's find y from (1):

y=925ft+(20ft/s)(6s)-\frac{1}{2}(32ft/s^{2})(6s)^{2} (2)

Finally:

y=469ft This is the height of the stone at t=6s

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2 years ago
What happens to parallel light rays that strike a concave lens?
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Due to the shape of the lens , parallel rays will be deviated
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A compact car, mass 660 kg, is moving at 1.00 ✕ 102 km/h toward the east. The driver of the compact car suddenly applies the bra
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Explanation:

Given

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change in momentum is given  by impulse imparted to the car

Impulse(J)=-F\cdot t

J=-4.8\times 10^3\times 2.1

J=-59.49\times 10^3 kg-m/s

negative Sign indicates that impulse is imparted opposite to the direction of motion

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