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FinnZ [79.3K]
2 years ago
8

The Surface Pressure at Leh, Ladakh is 800 mb. Now, assuming that Leh is at an altitude of 3500 m and every 100 m increase in he

ight with respect to sea level corresponds to 10 mb pressure, What is the Sea Level Pressure at Leh
Physics
1 answer:
Basile [38]2 years ago
8 0

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

<h3> Sea level pressure</h3>

Question Parameters:

Ladakh is 800 mb.

<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level <em>pressure</em> we need to add,

Ps=800+350

Ps= 1150 mb

For more information on Pressure visit

brainly.com/question/25688500

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Higher pay for teachers means students do better When teachers get paid more, students do better. In one study, a 10% increase in teacher pay was estimated to produce a 5 to 10% increase in student performance. Teacher pay also has long-term benefits for students.

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Which of these is an example of projectile motion?
Usimov [2.4K]

Answer:

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8 0
3 years ago
A 750 g air-track glider attached to a spring with spring constant 14.0 N/m is sitting at rest on a frictionless air track. A 20
alexandr402 [8]

Answer:

the amplitude of  the subsequent oscillations is 0.11  m

the period of the subsequent oscillations is 1.94 s

Explanation:

given Information:

the mass of air-track glider, m_{1} = 750 g = 0.75 kg

spring constant, k = 13.0 N/m

the mass of glider, m_{2} = 200 g = 0.2 kg

the speed of glider,  v_{2} = 170 cm/s = 1.7 m/s

the amplitude of  the subsequent oscillations is A = 0.11  m

according to mechanical enery equation, we have

A = \sqrt{\frac{m_{1} +m_{2} }{k} }v_{f}

where

A is the amplitude and  v_{f} is the final speed.

to find v_{f}, we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.

P_{f} = P_{i}

(m_{1} +m_{2} )v_{f} = m_{1} v_{1} +m_{2}v_{2}

v_{1} = 0, thus

(0.75+0.2)v_{f} = (0.75)(0)+(0.2)(1.7)

0.95 v_{f} = 0.34

v_{f} = 0.36 m/s

Now we can calculate the amplitude

A = \sqrt{\frac{0.75 +0.2 }{10} }0.36

A = 0.11  m

the period of the subsequent oscillations is T = 1.94 s

the equation for period is

T = 2π\sqrt{\frac{m_{1}+m_{2}  }{k} }

T = 2π\sqrt{\frac{0.75+0.2  }{10} }

T = 1.94 s

7 0
3 years ago
She leaves her campsite and runs north for 10 miles turns east and runs 8 miles then turns south and runs 2 miles.whats her dist
Mama L [17]

The distance is 20 miles

Explanation:

Definitions:

  • Distance is the total length of the path covered by an object during its motion, regardless of the direction of its motion
  • Displacement is the shortest distance between the initial and final position of the motion, so it also takes into account the direction of motion

In this problem, we want to know the distance covered by the woman. The motion consists of the following parts:

d_1 = 10 miles north

d_2 = 8 miles east

d_3 = 2 miles south

To find the distance, we just have to add the length of each path, ignoring the direction. Therefore:

d=d_1 + d_2 + d_3 = 10+8+2 = 20 miles

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