1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FinnZ [79.3K]
2 years ago
8

The Surface Pressure at Leh, Ladakh is 800 mb. Now, assuming that Leh is at an altitude of 3500 m and every 100 m increase in he

ight with respect to sea level corresponds to 10 mb pressure, What is the Sea Level Pressure at Leh
Physics
1 answer:
Basile [38]2 years ago
8 0

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

<h3> Sea level pressure</h3>

Question Parameters:

Ladakh is 800 mb.

<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level <em>pressure</em> we need to add,

Ps=800+350

Ps= 1150 mb

For more information on Pressure visit

brainly.com/question/25688500

You might be interested in
A woman is standing in the ocean, and she notices that after a wave crest passes, five more crests pass in a time of 54.0 s. The
timama [110]

Answer:

a) f=0.1 Hz ; b) T=10s

c)λ= 36m

d)v=3.6m/s

e)amplitude, cannot be determined

Explanation:

Complete question is:

Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.

Given:

number of wave crests 'n'= 5

pass in a time't' 54.0s

distance between two successive crests 'd'= 36m

a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have

f=n/t

f= 5/ 54 => 0.1Hz

b)The time period of wave 'T' is the reciprocal of the frequency

therefore,

T=1/f

T=1/0.1

T=10 sec.

c)wavelength'λ' is the distance between two successive crests i.e 36m

Therefore, λ= 36m

d) speed of the wave 'v' can be determined by the product of frequency and wavelength

v= fλ => 0.1 x 36

v=3.6m/s

e) For amplitude, no data is given in this question. So, it cannot be determined.

5 0
3 years ago
Which factors could be potential sources of error in the experiment? check all that apply.
Vadim26 [7]

(A)energy lost in the lever due to friction

(C) visual estimation of height of the beanbag

(E)position of the fulcrum for the lever affecting transfer of energy

6 0
3 years ago
Read 2 more answers
25 Points PLEASE I need Help
olga55 [171]

Answer:nah u took my points I take urs

Explanation:

6 0
3 years ago
A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the
Novay_Z [31]

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved

4 0
3 years ago
An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pip
OverLord2011 [107]

Answer:

The value is v_2 =  5.53 \  m /s

Explanation:

From the question we are told

  The pipe diameter at location 1 is  d  = 8.8 \  cm =  \frac{8.8 }{10} = 0.88 \ m

   The velocity at location 1 is  v_1 =  2.4 \  m /s

   The diameter at location 2 is  d_2 =  5.80 \  cm  =  0.58 \  m

Generally the area at location 1 is  

       A_1 =  \pi *  \frac{d^2}{ 2}

=>     A_1 =  \pi *  \frac{0.88^2}{ 2}

=>     A_1 = 3.142 *  \frac{0.88^2}{ 2}

=>     A_1 = 1.2166 \  m^2

Generally the area at location 1 is  

       A_2 =  \pi *  \frac{d_1^2}{ 2}

=>     A_2 =  \pi *  \frac{0.58^2}{ 2}

=>     A_2 = 0.528  \  m^2

Generally from continuity equation we have that

     A_1 * v_1 =  A_2 * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>   1.2166 *   2.4   =  0.528   * v_2

=>    v_2 =  5.53 \  m /s

3 0
3 years ago
Other questions:
  • A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c
    12·1 answer
  • What is the effect on the force of gravity between two objects if the mass of one object remains unchanged while the distance to
    5·1 answer
  • Artistic works in the animal style often contain ________ and images of abstracted animals.
    10·1 answer
  • A wooden block with mass 1.05 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 35.0 deg
    10·1 answer
  • If Angle "a" is 25°, Angle "b" is:
    5·1 answer
  • If a driver is tired, the thinking distance will be less. True or false.why?
    14·1 answer
  • A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction be
    11·1 answer
  • True or false: Equilibrium is the continual change from product to reactant and back.
    10·1 answer
  • A force Fof 40000 lbf is applied to rod AC the negative Y-direction. The rod is 1000 inches tall. A Force P of 25 lbf is applied
    11·1 answer
  • A 5. 0-c charge is 10 m from a small test charge. what is the magnitude of the force experienced by a 1. 0 nc charge placed at t
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!