In order to do this we have to get all the numbers into percent form.
60% = 60%
0.4 = 40%
1/5 = 0.2 = 20%
So, the order from smallest to biggest is 1/5, 0.4, and 60%.
((x^2)(y^2) - 9) *(3 - xy).
Note difference of two squares: (a^2 - b^2) = (a-b)(a+b)
(x^2)(y^2) - 9 = (xy)^2 - 3 ^2 = (xy - 3)(xy + 3). (Take note)
(3- xy) = -(xy - 3). (Take note of this also)
Your question said: ((x^2)(y^2) - 9) times (3 - xy),
Don't you think it should be divide? Would solve it as divide.
((x^2)(y^2) - 9) /(3 - xy) = (xy - 3)(xy + 3) / -(xy - 3)
= -(xy + 3).
Answer is (3). Solved it as divide. Using times gives none of the solution among the options.
Cheers.
I think it’s
m/3
Hope it helps you
